查找哪些用户正在使用相同的 JobID

Question

我只从 Google 电子表格中的每个用户 Sheet 提取 JobID 列。我想查询哪些用户正在使用相同的 JobID。我还需要将用户名列为查询的列，因为该列不存在于每个用户 Sheet 中，尽管 Sheet 名称是用户名。有没有办法使用 Google 查询来做到这一点？例如

JobID |  Count | Users using it                    |
----------------------------------------------------
1001  |   3    | alex, hubert, mark                |
1002  |   1    | mark                              |
1003  |   2    | sally, chaz, maha                 |
1004  |   1    | hubert                            |
1005  |   2    | maha, mark                        |

P.S：此外，Sheets 可以重命名为其他用户。所以需要一些动态的东西。

这里是 link 到 Sample file。

Answer 1

像下面这样的东西行得通吗？它动态地将 sheet 名称从“用户”选项卡中提取到“查询”。我想您还想先从该用户选项卡中删除报告和用户名。

这个在Report的C2里面，目前需要往下拖。我看看能不能想出一个数组公式。

=TEXTJOIN(", ",1,
 {IF(COUNTIF(INDIRECT(USERS!A & "!A:A"),A2),USERS!A,""), 
  IF(COUNTIF(INDIRECT(USERS!A & "!A:A"),A2),USERS!A,""),
  IF(COUNTIF(INDIRECT(USERS!A & "!A:A"),A2),USERS!A,""),
  IF(COUNTIF(INDIRECT(USERS!A & "!A:A"),A2),USERS!A,""),
  IF(COUNTIF(INDIRECT(USERS!A & "!A:A"),A2),USERS!A,""),
  IF(COUNTIF(INDIRECT(USERS!A & "!A:A"),A2),USERS!A,"") })

我只允许 6 个用户，但可以扩展到处理 10 到 20 个用户，使用 IF 或 IFERROR 测试来避免在任何时候“用户”选项卡中的用户较少时出现问题。

如果您对此有任何疑问，请告诉我。

更新#1 以下是扩展为允许 20 个用户的公式。只要将它们添加到 Users!A1:A20 中的任何位置，并且它们的 sheet 名称与其列出的名称相匹配，它们的值就会被包含在内。如果您发现任何问题，请告诉我。我仍然会尝试看看它是否可以变成一个数组公式。

=textjoin(", ",1,
 {if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""), 
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""), 
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""), 
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""), 
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""), 
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,""),
  if(countif(indirect(Users!A & "!A:A"),A2),Users!A,"")})

Answer 2

根据您的意见，我得到了 return JobID 和用户的单一公式。但是为了包括用户数量，我不得不添加另一列和公式。见下文：

D1中的关键公式如下：

={"Job ID","Users (hidden)";
  ArrayFormula(trim(split(regexreplace(REGEXREPLACE(transpose(query(query({
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0) },
     "select max(Col1) where Col2 <>'' group by Col1 pivot Col2",0)
     ,,99^99)),
     "♦️[0-9 ]+" , ", "),
     "(.*),", ""),
     "♥️",0)))}

此 return 是一组 JobID 和用户，以逗号分隔。它还包括 header 标签要添加用户数，按照您显示的格式，我隐藏了用户列，添加了一个计算用户数的列，然后添加了一个以下列复制了隐藏的用户列。如果您愿意，还有很多其他方法可以做到这一点。

下一个关键问题是，如果公式包含没有选项卡的用户（Users 中的一行），并且其中包含 JobID 作为数据，则公式将失败。有几种解决方法。
一种是额外的选项卡（20 个或您的最大用户数量），给它们命名，如 TEMP1、TEMP2 等，并在每个选项卡中有一个 JobID 作为填充符，值为 999999 或类似值。然后主公式查询可以排除具有该 JobID 的记录。这意味着每个用户查询总是 return 至少一个数据行，JobID 999999，并且不会失败。
当您获得新用户时，只需将用户选项卡中的 TEMP1 替换为他们的真实姓名，并将 TEMP1 选项卡重命名为他们的名字。

可能有其他错误检查可以防止这种情况，但我发现如果一个查询 return 没有行，堆叠多个查询会给我一个错误。例如：

{ query(indirect(Users!A & "!A:A").........);
  query(indirect(Users!A & "!A:A").........);
  query(indirect(Users!A & "!A:A").........);
  query(indirect(Users!A & "!A:A").........)   }

如果 User!A2 为空，或则出现错误 User!A2， 中没有与名称匹配的选项卡]或具有该名称的选项卡没有数据。

如果采取这些措施，则可以预设主要公式来处理二十个（或更多）用户。我上面显示的公式适用于当前的六个用户，但我已经用更多用户对其进行了测试。我会在底部提供二十个用户的公式。

如果这对您有帮助，或者您有任何疑问，请告诉我。很高兴回答他们。

二十个用户的公式。每个“用户”都有一个名字，或者一个虚拟名称占位符，在用户中，必须有一个带有该名称的选项卡，并且每个选项卡中必须至少有一个 JobID 值，或者一个虚拟的 JobID，可能像 999999。

={"Job ID","Users (hidden)";
  ArrayFormula(trim(split(regexreplace(REGEXREPLACE(transpose(query(query({
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0);
     query({ Users!A & "♦️" & row(indirect(Users!A & "!A:A")), indirect(Users!A & "!A:A")&"♥️"}, "where Col2<> '♥️'",0) },
     "select max(Col1) where Col2 <>'' group by Col1 pivot Col2",0)
     ,,99^99)),
     "♦️[0-9 ]+" , ", "),
     "(.*),", ""),
     "♥️",0)))}

查找哪些用户正在使用相同的 JobID

Find which users are working on the same JobID

google-sheets

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