HttpClient 已弃用/连接 PHP 服务器 - Android API 22

HttpClient deprecated / Connect with PHP server - Android API 22

我正在尝试登录并注册 android 应用程序。 我一直在将代码调整为 API 22 时遇到问题。 虽然我知道我必须使用 HttpURLConnection 而不是 HttpRequestParams 等,并且已经这样做了,但我不知道如何调整代码以合并数据库服务器和我的 PHP文件存储在那里。

主要是下面这一点我想不通

HttpClient client = new DefaultHttpClient(httpRequestParams);
HttpPost post = new HttpPost(SERVER_ADDRESS + "FetchUserData.php");

有人可以帮忙吗?提前致谢。

完整代码如下:

        @Override
        protected User doInBackground(Void... params) {

            ContentValues contentValues = new ContentValues();
            contentValues.put("username", user.username);
            contentValues.put("password", user.password);

            URL url = new URL(SERVER_ADDRESS);
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setConnectTimeout(CONNECTION_TIMEOUT);
            conn.setReadTimeout(CONNECTION_TIMEOUT);

            HttpClient client = new DefaultHttpClient(httpRequestParams);
            HttpPost post = new HttpPost(SERVER_ADDRESS + "FetchUserData.php");

            User returnedUser = null;
            try {
                post.setEntity(new UrlEncodedFormEntity(dataToSend));
                HttpResponse httpResponse = client.execute(post);

                HttpEntity entity = httpResponse.getEntity();
                String result = EntityUtils.toString(entity);
                JSONObject jObject = new JSONObject(result);

                if(jObject.length() == 0) {
                    returnedUser = null;
                } else {
                    String mobile = jObject.getString("mobile");
                    String email = jObject.getString("email");

                    returnedUser = new User(mobile, email, user.mobile, user.email);
                }

            } catch(Exception e) {
                e.printStackTrace();
            }

            return returnedUser;
        }

第一:已经回答了

其二:我做了一个满足你需求的class,一行代码就可以发送请求和接收响应(上面post中也有说明)

这是我的 class 的 link:

HttpRequest