过滤掉某些 XML 个节点，并与这些节点及其祖先和子节点形成另一个 XML

Question

我有以下 XML 数据，我需要过滤某些 XML 节点并使用这些节点及其祖先节点及其所有子节点形成另一个 XML 数据.我是 XSLT 的新手，尝试过使用 XSLT 的不同方法，但没有任何效果。

这能否在 XSLT 中实现？

数据：

<?xml version="1.0" encoding="UTF-8"?>
<MessageDetails>`enter code here`
   <challengeDetails>
      <challengeId>1000000017</challengeId>
      <challengeCode>WEEKACTIVE</challengeCode>
      <challengeCategory>StayActive</challengeCategory>
      <challengePeriodsDetails>
         <periodId>1000000064</periodId>
         <periodNumber>2</periodNumber>
         <periodStatus>INPROGRESS</periodStatus>
         <challengeAwardIssued>
            <awardType>GAME</awardType>
            <awardCode>GCH009</awardCode>
         </challengeAwardIssued>
         <challengeAwardIssued>
            <awardType>REWARD</awardType>
            <awardCode>EHNC001</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
      <challengePeriodsDetails>
         <periodId>1000000065</periodId>
         <periodNumber>3</periodNumber>
         <periodStatus>COMPLETED</periodStatus>
         <challengeAwardIssued>
            <awardType>REWARD</awardType>
            <awardCode>EHNC002</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
   </challengeDetails>
   <challengeDetails>
      <challengeId>1000000018</challengeId>
      <challengeCode>QUITSUGAR</challengeCode>
      <challengeCategory>QuitSugar</challengeCategory>
      <challengePeriodsDetails>
         <periodId>1000000066</periodId>
         <periodNumber>2</periodNumber>
         <periodStatus>INPROGRESS</periodStatus>
         <challengeAwardIssued>
            <awardType>REWARD</awardType>
            <awardCode>EHNC001</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
      <challengePeriodsDetails>
         <periodId>1000000067</periodId>
         <periodNumber>3</periodNumber>
         <periodStatus>COMPLETED</periodStatus>
         <challengeAwardIssued>
            <awardType>GAME</awardType>
            <awardCode>EHNC001</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
   </challengeDetails>
</MessageDetails>

搜索条件 #1：awardType = GAME

<?xml version="1.0" encoding="UTF-8"?>
<MessageDetails>
   <challengeDetails>
      <challengeId>1000000017</challengeId>
      <challengeCode>WEEKACTIVE</challengeCode>
      <challengeCategory>StayActive</challengeCategory>
      <challengePeriodsDetails>
         <periodId>1000000064</periodId>
         <periodNumber>2</periodNumber>
         <periodStatus>INPROGRESS</periodStatus>
         <challengeAwardIssued>
            <awardType>GAME</awardType>
            <awardCode>GCH009</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
   </challengeDetails>
   <challengeDetails>
      <challengeId>1000000018</challengeId>
      <challengeCode>QUITSUGAR</challengeCode>
      <challengeCategory>QuitSugar</challengeCategory>
      <challengePeriodsDetails>
         <periodId>1000000067</periodId>
         <periodNumber>3</periodNumber>
         <periodStatus>COMPLETED</periodStatus>
         <challengeAwardIssued>
            <awardType>GAME</awardType>
            <awardCode>GCH008</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
   </challengeDetails>
</MessageDetails>

搜索条件 #2：awardType = GAME and periodStatus = COMPLETED and challengeCode = QUITSUGAR

<?xml version="1.0" encoding="UTF-8"?>
<MessageDetails>
   <challengeDetails>
      <challengeId>1000000018</challengeId>
      <challengeCode>QUITSUGAR</challengeCode>
      <challengeCategory>QuitSugar</challengeCategory>
      <challengePeriodsDetails>
         <periodId>1000000067</periodId>
         <periodNumber>3</periodNumber>
         <periodStatus>COMPLETED</periodStatus>
         <challengeAwardIssued>
            <awardType>GAME</awardType>
            <awardCode>GCH008</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
   </challengeDetails>
</MessageDetails>

搜索条件 #3：challengeCode = WEEKACTIVE & periodId = 1000000064

    <?xml version="1.0" encoding="UTF-8"?>
    <MessageDetails>
       <challengeDetails>
          <challengeId>1000000017</challengeId>
          <challengeCode>WEEKACTIVE</challengeCode>
          <challengeCategory>StayActive</challengeCategory>
          <challengePeriodsDetails>
             <periodId>1000000064</periodId>
             <periodNumber>2</periodNumber>
             <periodStatus>INPROGRESS</periodStatus>
             <challengeAwardIssued>
                <awardType>GAME</awardType>
                <awardCode>GCH009</awardCode>
             </challengeAwardIssued>
          </challengePeriodsDetails>
       </challengeDetails>
    </MessageDetails>

搜索条件 #4：periodId = 1000000066

<?xml version="1.0" encoding="UTF-8"?>
<MessageDetails>
   <challengeDetails>
      <challengeId>1000000018</challengeId>
      <challengeCode>QUITSUGAR</challengeCode>
      <challengeCategory>QuitSugar</challengeCategory>
      <challengePeriodsDetails>
         <periodId>1000000066</periodId>
         <periodNumber>2</periodNumber>
         <periodStatus>INPROGRESS</periodStatus>
         <challengeAwardIssued>
            <awardType>REWARD</awardType>
            <awardCode>EHNC001</awardCode>
         </challengeAwardIssued>
      </challengePeriodsDetails>
   </challengeDetails>
</MessageDetails>

搜索条件 #5：awardType = 'GAME' 和 awardCode= 'EHNC001'

所需输出：

<?xml version="1.0" encoding="UTF-8"?>
<MessageDetails>`enter code here`
       <challengeDetails>
          <challengeId>1000000018</challengeId>
          <challengeCode>QUITSUGAR</challengeCode>
          <challengeCategory>QuitSugar</challengeCategory>
          <challengePeriodsDetails>
             <periodId>1000000067</periodId>
             <periodNumber>3</periodNumber>
             <periodStatus>COMPLETED</periodStatus>
             <challengeAwardIssued>
                <awardType>GAME</awardType>
                <awardCode>EHNC001</awardCode>
             </challengeAwardIssued>
          </challengePeriodsDetails>
       </challengeDetails>
    </MessageDetails>

收到的输出：

<?xml version="1.0" encoding="UTF-8"?>
<MessageDetails>`enter code here`
       <challengeDetails>
          <challengeId>1000000017</challengeId>
          <challengeCode>WEEKACTIVE</challengeCode>
          <challengeCategory>StayActive</challengeCategory>
          <challengePeriodsDetails>
             <periodId>1000000064</periodId>
             <periodNumber>2</periodNumber>
             <periodStatus>INPROGRESS</periodStatus>
          </challengePeriodsDetails>
       </challengeDetails>
       <challengeDetails>
          <challengeId>1000000018</challengeId>
          <challengeCode>QUITSUGAR</challengeCode>
          <challengeCategory>QuitSugar</challengeCategory>
          <challengePeriodsDetails>
             <periodId>1000000067</periodId>
             <periodNumber>3</periodNumber>
             <periodStatus>COMPLETED</periodStatus>
             <challengeAwardIssued>
                <awardType>GAME</awardType>
                <awardCode>EHNC001</awardCode>
             </challengeAwardIssued>
          </challengePeriodsDetails>
       </challengeDetails>
    </MessageDetails>

使用的 XSLT：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

<xsl:template match="/MessageDetails/challengeDetails[not(challengePeriodsDetails/challengeAwardIssued/awardType = 'GAME' and challengePeriodsDetails/challengeAwardIssued/awardCode= 'EHNC001')]" />

<xsl:template match="/MessageDetails/challengeDetails/challengePeriodsDetails[not(challengeAwardIssued/awardType = 'GAME' and challengeAwardIssued/awardCode= 'EHNC001')]" />

<xsl:template match="/MessageDetails/challengeDetails/challengePeriodsDetails/challengeAwardIssued[not(awardType = 'GAME' and awardCode= 'EHNC001')]" />

<xsl:mode on-no-match="shallow-copy" />
<xsl:output method="xml" indent="yes" />

</xsl:stylesheet>

Answer 1

据我了解，您想过滤掉 challengeDetails 和 challengePeriodsDetails 给定的一些谓词。要过滤掉 XSL 中的元素，您只需提供与不需要的元素相匹配的空模板。

查询 1

这是一个不错且简单的入门查询。只需从复制所有模板 node()|@* 开始，并添加两条规则以过滤掉不需要的内容。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

  <xsl:template match="/MessageDetails/challengeDetails[
      not(challengePeriodsDetails/challengeAwardIssued/awardType = 'GAME')
    ]" />

  <xsl:template match="/MessageDetails/challengeDetails/challengePeriodsDetails[
      not(challengeAwardIssued/awardType = 'GAME')
    ]" />

  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*" />
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

查询 2

这里的关键是过滤掉不满足两个谓词的challengePeriodsDetails。我们处理这些元素， 而不是 处理 challengeDetails，这就是谓词包含另一个谓词的原因。没有它，我们会过滤掉太多数据。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

  <xsl:template match="/MessageDetails/challengeDetails[
      not(challengePeriodsDetails[
        challengeAwardIssued/awardType = 'GAME' and periodStatus = 'COMPLETED'
      ])
    ]" />

  <xsl:template match="/MessageDetails/challengeDetails/challengePeriodsDetails[
      not(challengeAwardIssued/awardType = 'GAME' and periodStatus = 'COMPLETED')
    ]" />

  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*" />
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

查询 3

这里的特殊性是我们不需要担心challengePeriodsDetails模板中的challengeCode，因为它的父级无论如何都不会出现在最终文档中。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

  <xsl:template match="/MessageDetails/challengeDetails[
      not(challengeCode = 'WEEKACTIVE' and challengePeriodsDetails/periodId = '1000000064')
    ]" />

  <xsl:template match="/MessageDetails/challengeDetails/challengePeriodsDetails[
      not(periodId = '1000000064')
    ]" />

  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*" />
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

查询 4

这个看起来像查询 1，我只能建议您在查看代码之前尝试自己做，以证明自己有所改进。

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

  <xsl:template match="/MessageDetails/challengeDetails[not(challengePeriodsDetails/periodId = '1000000066')]" />

  <xsl:template match="/MessageDetails/challengeDetails/challengePeriodsDetails[not(periodId = '1000000066')]" />

  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*" />
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

查询 5

你们太亲密了！诀窍是针对相同的 challengeAwardIssued 测试 awardType 和 awardCode。您必须在此节点上使用测试。这是一个解决方案：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

  <xsl:template match="/MessageDetails/challengeDetails[
      not(challengePeriodsDetails/challengeAwardIssued[
        awardType = 'GAME' and awardCode = 'EHNC001'
      ])
    ]" />

  <xsl:template match="/MessageDetails/challengeDetails/challengePeriodsDetails[
      not(challengeAwardIssued[
        awardType = 'GAME' and awardCode = 'EHNC001'
      ])
    ]" />

  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*" />
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

过滤掉某些 XML 个节点，并与这些节点及其祖先和子节点形成另一个 XML

Filter out certain XML nodes and form another XML with these nodes and their ancestors and child nodes

xml

xslt

xsd

xml-parsing

xslt-3.0

查询 1

查询 2

查询 3

查询 4

查询 5