Oracle

Question

这是我的数据：

Step   random_task     Status         date
1        do_this      Completed       1-Nov-2020
1        do-that      Cancelled       2-Nov-2020
2        do_this     Not Assigned     1-Nov-2020
2        do_that      Cancelled       2-Nov-2020
2        and_that     Cancelled       2-Nov-2020
3        do_this      Cancelled       2-Nov-2020
3        do_that      Cancelled       2-Nov-2020
3        also_that    Cancelled       2-Nov-2020
4        do_that      In Progress or Scheduled or whatever   1-Nov-2020
4        and_that     Completed       2-Nov-2020

按步骤分组：

已完成=如果步骤中的所有任务都APS_Status__c=“已完成”。

已完成 = 如果至少有 1 个任务“已完成”并且所有剩余任务 =“已取消”。

未开始 = 如果至少有 1 个任务“未分配”并且所有剩余任务 =“已取消”。

未开始=如果步骤中的所有任务都APS_Status__c =“未分配”。

已取消=如果步骤中的所有任务都APS_Status__c =“已取消”。

进行中 = 如果至少有 1 个任务 <>“已完成”或“已取消”或“未分配”。

输出：

Step       Status            date 
1          Completed         2-Nov-2020 (if status = completed, then max(date) of that step
2          Not Started      (null)
3          Cancelled        (null)
4          In Progress      (null)

我试过为 100、-100 和 0 添加赋值，将其相加，然后提取 mod(sum,100) 以确定正确的值。但是我无法为该步骤分配最大（日期）。

Answer 1

您可以按如下方式使用 GROUP BY 和条件聚合：

SELECT STEP, STATUS, CASE WHEN STATUS = 'Completed' THEN DATE END AS DATE FROM
(SELECT STEP,
       DATE,
       CASE WHEN COMPLETED = TOTAL THEN 'Completed' 
            WHEN (COMPLETED >= 1 AND CANCELLED = TOTAL - COMPLETED) 
                 OR (NOTASSIGNED >= 1 AND CANCELLED = TOTAL - NOTASSIGNED) THEN 'Cancelled'
            WHEN NOTASSIGNED = TOTAL THEN 'Not Assigned'
            WHEN CANCELLED = TOTAL THEN 'Cancelled'
        END AS STATUS
FROM
(SELECT STEP,
       COUNT(CASE WHEN STATUS = 'Completed' THEN 1 END) AS COMPLETED,
       COUNT(CASE WHEN STATUS = 'Cancelled' THEN 1 END) AS CANCELLED,
       COUNT(CASE WHEN STATUS = 'Not Assigned' THEN 1 END) AS NOTASSIGNED,
       COUNT(CASE WHEN STATUS = 'In Progress' THEN 1 END) AS INPROGRESS,
       COUNT(1) AS TOTAL,
       MAX(DATE) AS DATE
FROM YOUR_TABLE
GROUP BY STEP))

我不确定正在进行中的情况，请自行处理。

Answer 2

您可以使用条件聚合作为：

select step,
       (case when min(status) = max(status) and min(status) in ('Completed', 'Cancelled')
             then min(status)
             when sum(case when status in ('Completed', 'Cancelled') then 1 else 0 end) = count(*)
             then 'Completed'
             when sum(case when status in ('Not Assigned', 'Cancelled') then 1 else 0 end) = count(*)
             then 'Not Started'
             then ''
             else 'In Progress'
       end) as status,
       (case when min(status) = max(status) and min(status) in 'Completed'
             then max(date)
        end)
from t
group by step;

这些稍微简化了您的逻辑。特别是，“已完成”和“已取消”在逻辑中首先处理——如果所有状态都相同。如果所有状态均为“未分配”或“已取消”，则步骤为“未开始”。

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sql

plsql

oracle12c