按关系字段计数排序

Question

我有以下关系：

Member一对多Product

Product 多对一 Member

这是我有效的查询：

$qb = $this->createQueryBuilder('m');
$qb
    ->where('m.Authority = :Authority')
    ->setParameter('Authority', Authority::CREATOR)
    ->innerJoin('m.Product', 'p')
    ->select('COUNT(p) AS HIDDEN item_count', 'm')
    ->groupBy('m')
    ->orderBy("item_count", "ASC");

然而，当我为产品状态添加额外的参数时

$qb = $this->createQueryBuilder('m');
$qb
    ->where('m.Authority = :Authority')
    ->setParameter('Authority', Authority::CREATOR)
    ->andWhere('p.Status = :Status')
    ->setParameter('Status', 1);
    ->innerJoin('m.Product', 'p')
    ->select('COUNT(p) AS HIDDEN item_count', 'm', 'p')
    ->groupBy('p')
    ->orderBy("item_count", "ASC");

订单不再发生。我转储了 item_count 的值，它始终是 1。有没有人遇到过同样的问题？此处的目标是获取状态为 1 且按产品数量排序的产品的成员列表。

编辑：如果我将 groupBy('p') 更改为 groupBy('m')，它只会为每个 Member

加载一个相关的 Product

Answer 1

对于遇到同样问题的任何人，我就是这样做的：

$qb = $this->createQueryBuilder('m');
$qb
    ->where('m.Authority = :Authority')
    ->setParameter('Authority', Authority::CREATOR)
    ->andWhere('p.Status = :Status')
    ->setParameter('Status', 1);
    ->select('p, m')
    ->addSelect('(SELECT COUNT(DISTINCT p1)
    FROM Eccube\Entity\Member m1
    INNER JOIN Eccube\Entity\Product p1
    WHERE m1.Authority = ' . Authority::CREATOR . ' AND p1.Status = 1 AND p1.Creator = m.id
    ) AS hidden item_count')
    ->innerJoin('m.Product', 'p')
    ->groupBy('p')
    ->orderBy("item_count", "ASC");

有效，但我不明白为什么会这样 p1.Creator = m.id？如果我使用 m1.id，它只会总结项目数。

编辑：在 Jakumi 关于加入的评论之后添加了更新的代码。尽管两个代码都有效，但第二个代码更有意义。

$qb = $this->createQueryBuilder('m');
$qb
    ->where('m.Authority = :Authority')
    ->setParameter('Authority', Authority::CREATOR)
    ->andWhere('p.Status = :Status')
    ->setParameter('Status', 1);
    ->select('p, m')
    ->addSelect('(SELECT COUNT(DISTINCT p1)
    FROM Eccube\Entity\Member m1
    INNER JOIN m1.Product p1
    WHERE m1.Authority = ' . Authority::CREATOR . ' AND p1.Status = 1 AND p1.Creator = m
    ) AS hidden item_count')
    ->innerJoin('m.Product', 'p')
    ->groupBy('p')
    ->orderBy("item_count", "ASC");

按关系字段计数排序

Order by count of relational field

php

symfony

doctrine-orm