字母表的并列整数 ASCII 码

Question

我想通过并列字母表的整数 ASCII 代码将姓名和姓氏（例如 Nova Stark）转换为大整数，打印相应的转换后的整数，然后将大整数切成两半并将两个相加 halves.Following 是我的方法：-

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

    char* arr2str(int arr[], int size) {
        static char buffer[256];
        memset(&buffer[0], 0, sizeof(buffer)/sizeof(char));
        char *ptr = &buffer[0];
        for(int i=0; i<size; ++i) {
            sprintf(ptr += strlen(ptr), "%d", arr[i]);
        }
        return buffer;
    }

    int arr2int(int arr[], int size)
       {
        char buffer[256] = {0,};
        char *ptr = &buffer[0];
        for(int i = 0; i < size; ++i) {
            sprintf(ptr += strlen(ptr), "%d", arr[i]);
        }
        return atoi(&buffer[0]);
    }

int main()
{
    int *A;
    long long int num;
    int div,base=10;
    char name[50],asc[200];
    printf("Enter your name : ");
    scanf(" %[^\n]",name);
    int len=strlen(name);
    A=(int*)malloc(len*sizeof(int));
    for(int i=0;i<len;i++)
    {
        A[i]=name[i];

    }
    char *str = arr2str(A, len);  //for converting array to string
    num = arr2int(A, len);         //again for converting the character array to integer.
    //num=array_to_num(A,len);
    div=base;
    while(num/div>div)
    {
        div=div*base;
    }
    long long int a=num/div;
    long long int b=num%div;
    long long int c=a+b;
    printf("The required integer is %lld and the sum is %lld ",num,c);
    return 0;
}

但是我没有得到想要的输出。请帮忙！另外，如果存在解决该问题的更简单方法，也请说明。

Answer 1

以下是运行，解释见代码注释。也许您必须处理名称中的空格：

#include<stdio.h>
#include<stdlib.h>
#include<string.h>



int main()
{
    int *A;
    long long int num;
    int div,base=10;
    char name[50];
    printf("Enter your name : ");
    scanf(" %[^\n]",name);
    int len=strlen(name);
    A=(int*)malloc(len*sizeof(int));
    for(int i=0;i<len;i++)
    {
        *(A+i)=(int)name[i];  // *(A+i) is accessing array as pointer+index : https://www.programiz.com/c-programming/c-dynamic-memory-allocation 
    // letters to ascii is done by simply typecasting to (int)

    }
    
    // string to int array
    
    for(int i=0;i<len;i++)
    {
        printf("%i -> %c \n", *(A+i), (char)(*(A+i)));

    }
     
     
    // long long int from concatenating the elements of the int array 
    
    
    int s_idx=0; // index for string
    char str[512];  //string of fixed size, possibly malloc this
     
    for (int i=0; i<len; i++)
    s_idx += snprintf(&str[s_idx], 512-s_idx, "%d", *(A+i));
    
    printf("%s \n", str);
   

    num = strtoll(str, NULL, 10);  // https://en.cppreference.com/w/c/string/byte/strtol

    
    // from here your code is unchanged
    
    
    div=base;
    while(num/div>div)
    {
        div=div*base;
    }
    long long int a=num/div;
    long long int b=num%div;
    long long int c=a+b;
    printf("The required integer is %lld and the sum is %lld \n ",num,c);
    free(A);
    return 0;
}

字母表的并列整数 ASCII 码

Juxtaposing integer ASCII codes for alphabet

c

arrays

string

ascii