在 Graphviz 的嵌套子图中放置节点
Placement of nodes in a nested subgraph in Graphviz
我正在尝试创建一个二元图,用不同的颜色着色和标记不同的节点。
为了获得子树周围的边界,我使用了几乎完美无缺的子图:
graph G
{
graph [ranksep="0.25", nodesep="0.25"]
rankdir = TB;
node [shape=ellipse, style=filled, fillcolor="#0068B4", color=white, fontcolor=white, penwidth=10]
edge [arrowtail="none"]
subgraph cluster_0 {
node [fillcolor="#99CC00"]
color="#99CC00"
style=filled
fillcolor=white
fontcolor="#99CC00"
label="12 is the root of\n26's left child\r"
18;
subgraph cluster_01 {
node [fillcolor="#00B0F0"]
color="#00B0F0"
fontcolor="#00B0F0"
style=filled
fillcolor=white
label="4 is the root of \n12's left child \r"
7 [fillcolor=white]
4 -- 13
4 -- 7 [style=invisible]
7 -- 13 [style=invisible]
{ rank=same; 7, 13 }
{ rank=same; 4, 18 }
}
12 -- {4,18}
{ rank=same; 12 }
}
subgraph cluster_1 {
node [fillcolor="#C00000"]
color="#C00000"
style=filled
fillcolor=white
fontcolor="#C00000"
label="32 is the root of\n26's right child\r"
35 [fillcolor=white]
32 -- 38
32 -- 35 [style=invisible]
35 -- 38 [style=invisible]
{ rank=same; 32 }
{ rank=same; 35, 38 }
}
26 -- {12, 32}
{ rank=same; 26 }
}
导致此输出:
如您所见,节点 18 位于蓝色子集群内。除了在 4 和 18 之间放置一个空白虚拟节点(如不可见节点 7 和 35)之外,是否有一种简单的方法可以将该节点“开箱即用”?
但是,添加 graph [newrank=true]
并重新排列几行会使事情变得更好:
graph G
{
graph [ranksep="0.25", nodesep="0.25" newrank=true]
rankdir = TB;
node [shape=ellipse, style=filled, fillcolor="#0068B4", color=white, fontcolor=white, penwidth=10]
edge [arrowtail="none"]
subgraph cluster_0 {
node [fillcolor="#99CC00"]
color="#99CC00"
style=filled
fillcolor=white
fontcolor="#99CC00"
label="12 is the root of\n26's left child\r"
subgraph cluster_01 {
node [fillcolor="#00B0F0"]
color="#00B0F0"
fontcolor="#00B0F0"
style=filled
fillcolor=white
label="4 is the root of \n12's left child \r"
7 [fillcolor=white]
4 -- 13
4 -- 7 [style=invisible]
7 -- 13 [style=invisible]
{ rank=same; 7, 13 }
}
{ rank=same; 4, 18 }
12 -- {4,18}
{ rank=same; 12 }
}
subgraph cluster_1 {
node [fillcolor="#C00000"]
color="#C00000"
style=filled
fillcolor=white
fontcolor="#C00000"
label="32 is the root of\n26's right child\r"
35 [fillcolor=white]
32 -- 38
32 -- 35 [style=invisible]
35 -- 38 [style=invisible]
{ rank=same; 32 }
{ rank=same; 35, 38 }
}
26 -- {12, 32}
{ rank=same; 26 }
}
给出:
我正在尝试创建一个二元图,用不同的颜色着色和标记不同的节点。
为了获得子树周围的边界,我使用了几乎完美无缺的子图:
graph G
{
graph [ranksep="0.25", nodesep="0.25"]
rankdir = TB;
node [shape=ellipse, style=filled, fillcolor="#0068B4", color=white, fontcolor=white, penwidth=10]
edge [arrowtail="none"]
subgraph cluster_0 {
node [fillcolor="#99CC00"]
color="#99CC00"
style=filled
fillcolor=white
fontcolor="#99CC00"
label="12 is the root of\n26's left child\r"
18;
subgraph cluster_01 {
node [fillcolor="#00B0F0"]
color="#00B0F0"
fontcolor="#00B0F0"
style=filled
fillcolor=white
label="4 is the root of \n12's left child \r"
7 [fillcolor=white]
4 -- 13
4 -- 7 [style=invisible]
7 -- 13 [style=invisible]
{ rank=same; 7, 13 }
{ rank=same; 4, 18 }
}
12 -- {4,18}
{ rank=same; 12 }
}
subgraph cluster_1 {
node [fillcolor="#C00000"]
color="#C00000"
style=filled
fillcolor=white
fontcolor="#C00000"
label="32 is the root of\n26's right child\r"
35 [fillcolor=white]
32 -- 38
32 -- 35 [style=invisible]
35 -- 38 [style=invisible]
{ rank=same; 32 }
{ rank=same; 35, 38 }
}
26 -- {12, 32}
{ rank=same; 26 }
}
导致此输出:
如您所见,节点 18 位于蓝色子集群内。除了在 4 和 18 之间放置一个空白虚拟节点(如不可见节点 7 和 35)之外,是否有一种简单的方法可以将该节点“开箱即用”?
但是,添加 graph [newrank=true]
并重新排列几行会使事情变得更好:
graph G
{
graph [ranksep="0.25", nodesep="0.25" newrank=true]
rankdir = TB;
node [shape=ellipse, style=filled, fillcolor="#0068B4", color=white, fontcolor=white, penwidth=10]
edge [arrowtail="none"]
subgraph cluster_0 {
node [fillcolor="#99CC00"]
color="#99CC00"
style=filled
fillcolor=white
fontcolor="#99CC00"
label="12 is the root of\n26's left child\r"
subgraph cluster_01 {
node [fillcolor="#00B0F0"]
color="#00B0F0"
fontcolor="#00B0F0"
style=filled
fillcolor=white
label="4 is the root of \n12's left child \r"
7 [fillcolor=white]
4 -- 13
4 -- 7 [style=invisible]
7 -- 13 [style=invisible]
{ rank=same; 7, 13 }
}
{ rank=same; 4, 18 }
12 -- {4,18}
{ rank=same; 12 }
}
subgraph cluster_1 {
node [fillcolor="#C00000"]
color="#C00000"
style=filled
fillcolor=white
fontcolor="#C00000"
label="32 is the root of\n26's right child\r"
35 [fillcolor=white]
32 -- 38
32 -- 35 [style=invisible]
35 -- 38 [style=invisible]
{ rank=same; 32 }
{ rank=same; 35, 38 }
}
26 -- {12, 32}
{ rank=same; 26 }
}
给出: