Django 中的列表分页

Question

我想对图书列表进行分页。 api终点是这样的/books?page=num&size=num 所以页数和加载多少本书将是变量。

我的回复应该是这样的：

{
  pagesnum= totalpages
  booksnum=totalbooks
  books=
  [ {detailsofbook1},
    {...},
    {...}
  ]
}

我的代码：

网址格式：

path('api/books?page=<int:page>&size=<int:size>/',BookView.as_view()),

views.py

class BookView(APIView):
    http_method_names = ['get']
    permission_classes = (permissions.IsAuthenticated,)

    def index(request):
            books = Books.objects.all()

            books_per_page= request.GET.get('size')
            book_paginator = Paginator(books, books_per_page)

            page_num = request.GET.get('page')

            page = book_paginator.get_page(page_num)

            context = {
                'count': book_paginator.count(),
                'page': page
            queryset =Books.ojects.all()  
            }
            return JsonResponse(context, status=200)

This implementation doesn't work. First of all something is wrong probably with the url it doesnt seem to understand the variables. Or is something else wrong with my code?

Answer 1

page 和 size 是 query parameters，所以你通过访问 request.query_params 得到它们，所以它应该像

        books_per_page= request.query_params.get('size') # or request.query_params['size]
        page_num = request.query_params.get('page')

另外，我对 index() 有点困惑我认为你的代码应该在 get(self, request, *args, **kwargs)

最后一件事是您可以在 DRF 中使用分页，see

Django 中的列表分页

List pagination in Django

django

api

django-rest-framework

pagination

django-pagination