到目前为止，我如何在没有 "Present" 元素的数组中填写缺席的所有日期？

Question

让我们假设下面是一个包含员工出勤数据的数组（使用Ajax从Mongo获取）：

[{"_id":"5fcdcd49c3657d1e05b846f5","title":"Present","allDay":true,"start":"2020-11-20","display":"background","color":"#4caf50"},
{"_id":"5fcdcd74c3657d1e05b846f6","title":"Present","allDay":true,"start":"2020-12-07","display":"background","color":"#4caf50"},
{"_id":"5fcebc7653057438acc633a6","title":"Present","allDay":true,"start":"2020-12-08","display":"background","color":"#4caf50"},]

此数组由 JSON 格式的元素组成。 当读取数组时，我们发现在每个元素中，JSON 对象包含两个字段 - Start（提到日期）和 Title（提到员工是否在场）

现在，我们注意到在 (2020-11-20) 上有一个元素表明该员工在场。然后是下一个元素，说明该员工在 2020-12-07（大约 17 天后）在场。根据我的用例，我假设该员工已经缺勤 17 天。

现在，这17天是-

2020-11-21
2020-11-22
2020-11-23 ...
至 2020-12-06

我愿意：

$.ajax(
{
url: "/api/employees/markAttendence/Absent/:date" [We will fill the date obviously, I have left it as :date for illustration]
type: "GET"
}
);

员工缺勤的每一天。

我想用moment.js从今天减去天数，检查元素是否存在并计算出日期时刻。如果没有元素，我会发送上面的 Ajax 那个日期的请求。

我该怎么做？

Answer 1

我不知道你做了多少所以我们从数据处理开始。

根据给定的数据，我想将开始信息提取到一个名为 presentDate 的数组中。

var dataset = [{"_id":"5fcdcd49c3657d1e05b846f5","title":"Present","allDay":true,"start":"2020-11-20","display":"background","color":"#4caf50"},
               {"_id":"5fcdcd74c3657d1e05b846f6","title":"Present","allDay":true,"start":"2020-12-07","display":"background","color":"#4caf50"},
               {"_id":"5fcebc7653057438acc633a6","title":"Present","allDay":true,"start":"2020-12-08","display":"background","color":"#4caf50"},]

var presentDate = dataset.filter(data => data.title === "Present").map(data => data.start);

我尝试与 Moment.js 一起工作，并回顾了大约 30 天。查看 presentDate 中是否存在任何日期并跳过它们。

var today = moment(moment().format('YYYY-MM-DD'));
var lookBackDays = 30;
var NeedToQuery = [];
for(var index = 1; index <= lookBackDays; ++index) {
    var checkDate = moment(today);
    checkDate.subtract(index, 'days');
    var dateString = checkDate.format('YYYY-MM-DD');
    if(presentDate.indexOf(dateString) < 0)
    {
        // Here I store the date string into NeedToQuery
        NeedToQuery.push(dateString);
    }
}

最后你会有日期字符串来发送 Ajax 请求，祝你好运。

Answer 2

谢谢@ian00！我也找到了一个很好用的解决方案。

function markAbsentism() {
        $.ajax({
          url: "/******/******/*******/",
          type: "GET",
        }).done((result) => {
          var presentDates = [],
            excludedDates = [];
          if (
            moment(result[result.length - 1].start).diff(
              moment(result[result.length - 2].start),
              "days"
            ) == 1 &&
            (result[result.length - 1].title == "Present" ||
              result[result.length - 1].title == "Absent") &&
            (result[result.length - 2].title == "Present" ||
              result[result.length - 2].title == "Absent")
          ) {
            console.log("IF_1 SUCCESS");
            return;
          } else {
            console.log("IF_1 FAILED");
            console.log("ELSE_1 EXEC STARTED");
            for (let ctr = result.length - 1; ctr >= 0; ctr--) {
              if (
                result[ctr].title == "Present"
              ) {
                if (presentDates.length <= 2) {
                  console.log("EMPLOYEE PRESENT");
                  presentDates.push(result[ctr].start);
                  excludedDates.push(result[ctr].start);
                } else {
                  console.log("GOT 2 PRESENT DATES. BREAKING LOOP");
                  break;
                }
              } else if (
                result[ctr].title == "Leave" ||
                result[ctr].title == "Holiday" ||
                result[ctr].title == "Half-Day"
              ) {
                console.log("EMPLOYEE IN LEAVE");
                excludedDates.push(result[ctr].start);
              }
            }
            console.log(presentDates);
            console.log(excludedDates);
          }

          console.log("Proceeding to For Loop");

          for (
            let i = 0;
            i <= moment(presentDates[0]).diff(moment(presentDates[1]), "days");
            i++
          ) {
            if (
              excludedDates.includes(
                moment(presentDates[1]).add(i, "days").format("YYYY-MM-DD")
              )
            ) {
              console.log("EXCLUDED DATE CAUGHT CONTINUING");
              continue;
            } else {
              console.log("SENDING AJAX REQUEST");
              $.ajax({
                url:
                  "/******/******/*******/" +
                  moment(presentDates[1]).add(i, "days").format("YYYY-MM-DD"),
                type: "GET",
              });
            }
          }
        });
      }

我会试一试你的，找到最有效的。

到目前为止，我如何在没有 "Present" 元素的数组中填写缺席的所有日期？

How do I fill absent on all days in an array till now which are not having the "Present" Element?

html

javascript

arrays

ajax

momentjs