如何使用 Newtonsoft.Json 从 JSON 子数组中获取数据?

How to get data from JSON sub array using Newtonsoft.Json?

我更新了 JSON table,如下所示

{ "Students" : [ {"name": "Alex", "lastname": "Dean", "Properties" : [{"iq":120, "hair": "black", "glasses": "yes", "Grades": [{"Math": 44, "Lit": "88"}]}, {"iq":120, "hair": "blond", "glasses": "yes", "Grades" : [{"Math": 22, "Lit": "81"}]}, {"iq":144, "hair": "brown", "glasses": "yes", "Grades": [{"Math": 44, "Lit": "88"}]}, {"iq":120, "hair": "red", "glasses": "yes", "Grades" : [{"Math": 44, "Lit": "88"}]}]}]}

我设法获取了不在子数组中的名字和姓氏,但无法弄清楚如何获取子数组中的其他数据。在数组 "Students" 中有一个名为 "Properties" 的子数组,在 "Properties" 中有另一个名为 "Grades".

的子数组

如何获得 "hair" 和 "math" 属性?

这是我获取名字和姓氏的方法。

这是我的网络服务class

public class WebService
    {
        public WebService ()
        {

        }

        public async Task<Rootobject> GetStudentInfoAsync (string apiurl) {

            var client = new HttpClient (); 

            var response = await client.GetStringAsync(string.Format(apiurl));

            return JsonConvert.DeserializeObject<Rootobject>(response.ToString());

        }
    }

这是我想出的视图模型。为什么它不起作用。我没有得到值。

namespace MyApp
{
    public class Grade
    {
        public string Math { get; set; }
        public string Lit { get; set; }

    }

    public class Property
    {

        public int iq { get; set; }
        public string hair { get; set; }
        public string glasses { get; set; }

        public Grade[] Grades { get; set; }

    }
    public class StudentInfo
    {
        public string name { get; set; }
        public string lastname { get; set; }

        public Property[] Properties { get; set; }

        public string StudentName {
            get{ return String.Format ("{0}", name); }
        }
//Why isn't the following code work? I am not getting the values and I get errors.

        public string HairColor {
            get{ return String.Format ("{0}",Property.hair); }
        }
        public string MathGrade {
            get{ return String.Format ("{0}", Property.Grade.Math); }
        }

    }

    public class Rootobject
    {
        public StudentInfo[] students { get; set; }

    }
}

下面是我如何使用学生姓名填充列表视图

var sv = new WebService();
            var es = await sv.GetStudentInfoAsync(apiurl);
            Xamarin.Forms.Device.BeginInvokeOnMainThread( () => {

                listView.ItemsSource = es.students;
            });
var cell = new DataTemplate (typeof(TextCell));

            listView.ItemTemplate = cell;
            listView.ItemTemplate.SetBinding(TextCell.TextProperty, "StudentName");

问题是您正在尝试访问一个名为 Property 的 属性,它在您的 class 中不存在。相反,您的 class 有一个 Property 对象数组:

    public Property[] Properties { get; set; }

同样,您的 Property class 有一个 Grade 对象数组,而不是单个 Grade:

    public Grade[] Grades { get; set; }

因此您必须对数组进行索引才能找到特定的 PropertyGrade。如果你总是想在每个数组中使用第一个条目,这可以通过Enumerable.Select and Enumerable.FirstOrDefault:

轻松完成
public class StudentInfo
{
    public string name { get; set; }
    public string lastname { get; set; }

    public Property[] Properties { get; set; }

    public string StudentName {
        get{ return String.Format ("{0}", name); }
    }
    public string HairColor {
        get{ return (Properties ?? Enumerable.Empty<Property>()).Select(p => p.hair).FirstOrDefault(); }
    }

    public string MathGrade {
        get { return (Properties ?? Enumerable.Empty<Property>()).SelectMany(p => p.Grades ?? Enumerable.Empty<Grade>()).Select(g => g.Math).FirstOrDefault(); }
    }
}

然后,进行测试:

        var root = JsonConvert.DeserializeObject<Rootobject>(response);
        Debug.Assert(root.students.Length == 1 && root.students[0].HairColor == "black" && root.students[0].MathGrade == "44"); // No assert.

更新

您不能将“'hair' of all 4 students”作为 StudentInfo 的 属性,因为在您的 JSON 中,每个学生只有一个条目在其 "Properties" 数组中。如果你 post 你的 JSON 到 http://jsonformatter.curiousconcept.com/,你可以更清楚地看到这一点。要获取所有学生的头发颜色或姓名,您需要根对象:

        var root = JsonConvert.DeserializeObject<Rootobject>(response);

        var hairColors = root.students.Select(s => s.HairColor).ToArray();
        var studentNames = root.students.Select(s => s.StudentName).ToArray();

更新 2

在您更新的问题中,单个 "student" 对象确实具有多个头发颜色属性、多个数学成绩等。在这种情况下,如果您希望将它们显示为单个字符串,则需要以某种方式组合它们,例如以逗号分隔值:

public class StudentInfo
{
    public string name { get; set; }

    public string lastname { get; set; }

    public Property[] Properties { get; set; }

    public string StudentName
    {
        get { return name; }
    }

    public string[] HairColors
    {
        get
        {
            return (Properties ?? Enumerable.Empty<Property>()).Select(p => p.hair).ToArray();
        }
    }

    public string HairColorCSV
    {
        get { return string.Join(",", HairColors); }
    }

    public string[] MathGrades
    {
        get
        {
            return (Properties ?? Enumerable.Empty<Property>()).SelectMany(p => p.Grades ?? Enumerable.Empty<Grade>()).Select(g => g.Math).ToArray();
        }
    }

    public string MathGradeCSV
    {
        get { return string.Join(",", MathGrades); }
    }
}