仅仅声明环境变量 openURL 会导致弹出窗口行为不稳定

Question

如以下示例代码所示。当运行没有声明 openURL 变量时，弹出窗口正确显示。取消注释这些行，它出现在不正确的位置并拒绝被驳回。我真的可以使用 fix/work-around...

struct Popover: View {
    @State var isShowingPopover = false
//    @Environment(\.openURL) var openURL

    var body: some View {
        Text("Content")
        .toolbar {
            ToolbarItemGroup(placement: .primaryAction) {
                Button("Popover") {
                    isShowingPopover.toggle()
                }
                .popover(isPresented: $isShowingPopover) {
                    Button(action:{
//                        openURL(URL(string: "https://cnn.com")!)
                    }){
                        Label("Open CNN", systemImage: "hand.thumbsup")
                    }
                        .padding()
                }
            }
        }
    }
}


struct Popover_Previews: PreviewProvider {
    static var previews: some View {
        NavigationView{
            Text("Sidebar")
            Popover()
        }
    }
}

Answer 1

出现 toolbar 缺陷...使用 navigationBarItems 工作正常。

测试 Xcode 12.1 / iOS 14.1

struct PopoverView: View {
    @State var isShowingPopover = false
    @Environment(\.openURL) var openURL

    var body: some View {
        Text("Content")
            .navigationBarItems(trailing:
                 Button("Popover") {
                      isShowingPopover.toggle()
                 }
                 .popover(isPresented: $isShowingPopover) {
                      Button(action:{
                            openURL(URL(string: "https://cnn.com")!)
                      }){
                            Label("Open CNN", systemImage: "hand.thumbsup")
                      }
                            .padding()
                 })
    }
}

仅仅声明环境变量 openURL 会导致弹出窗口行为不稳定

Merely declaring the environment variable openURL cause popover behavior to go wonky

swiftui

popover

openurl