为什么同一个 argv[] 在两个线程中打印了两次？

Question

我刚开始在多线程中编程并修改一些模板，我生成了这段可能很糟糕的代码：

#include <stdio.h>

#include <pthread.h>

#include <assert.h>

#include <stdlib.h>

#include <string.h>

typedef struct __myarg_t //argument struct?
{

    int a;

    char *b;

} myarg_t;

typedef struct __myret_t //return thread struct?
{

    int x;

    char *y;

} myret_t;

char cat[100] = ""; //used for concatenation of argv 

void *mythread(void *arg)
{

    myarg_t *m = (myarg_t *)arg;

    int print_index = 0;
    printf("THREAD ID:  %lu\n", pthread_self());
    for (print_index = 0; print_index < m->a; print_index++)
    {
        printf("Printing %d th character %c\n", print_index, *(m->b + print_index));//spelling the words 
    }

    myret_t *rfin = malloc(sizeof(myret_t));

    rfin->x = 1;
    strcat(cat, m->b);//concatenating argv with
    strcat(cat, " "); //a space to cat
    rfin->y = cat;//reassigning the new sentence to rfin
    return (void *)rfin;
}

int main(int argc, char *argv[])
{
    if (argc == 1)
    {
        printf("Enter a word as argument before commandline.\nExiting...\n");
        exit(0);
    }

    int rc = 0;

    pthread_t p[argc - 1]; //total threads

    myret_t *m; //return thread

    myarg_t args; //argument thread?

    int i = 1;
    while (i < argc) //creating threads:
    {
        printf("THREAD:\t%d\n", i);
        args.a = strlen(argv[i]);

        args.b = (char *)malloc(strlen(argv[i]));

        strcpy(args.b, argv[i]);

        pthread_create(&p[i - 1], NULL, mythread, &args);

        i++;
    }
    i = 1;
    while (i < argc) // Wait for threads to complete
    {
        pthread_join(p[i - 1], (void **)&m);
        i++;
    }

    printf("returned %d %s\n", m->x, m->y); //end concatenation result for myret_t *m;

    return 0;
}

所以当我执行它时：

gcc -g task2.c -o thread -Wall -pthread
./thread hello there

结果如下：

THREAD: 1
THREAD: 2
THREAD ID:      139848453601024
Printing 0 th character t
Printing 1 th character h
Printing 2 th character e
Printing 3 th character r
Printing 4 th character e
THREAD ID:      139848445208320
Printing 0 th character t
Printing 1 th character h
Printing 2 th character e
Printing 3 th character r
Printing 4 th character e
returned 1 there there

而不是 hello there。我连接的方式有问题吗？我应该使用另一个线程来做吗？

我是否应该锁定代码的串联部分，因为不同的线程正在同时使用它？

知道我哪里出错了吗？任何 help/advice/criticism 都非常受欢迎。

Answer 1

您的代码中存在竞争条件——您将指向 args 的指针传递给第一个线程，然后 main() 函数立即覆盖对象中的成员变量指针指向，而第一个线程是运行并行的，所以第一个线程（通常）在被覆盖之前没有机会看到原始的 args.a 或 args.b 值.为避免这种情况，您可以为每个线程分配一个单独的 args 结构，而不是：

    myarg_t * args = (myarg_t *) malloc(sizeof(myarg_t));
    args->a = strlen(argv[i]);
    args->b = (char *)malloc(strlen(argv[i])+1);  // +1 for NUL terminator byte
    strcpy(args->b, argv[i]);
    pthread_create(&p[i - 1], NULL, mythread, args);

为什么同一个 argv[] 在两个线程中打印了两次？

Why is the same argv[] printed twice in the two threads?

c

multithreading

pthreads

pthread-join