如何在不复制内容的情况下循环遍历已经在 map 函数中的数组
How to loop over a an array that is already inside a map function without duplicating the contents
我有以下代码和以下数组。我想遍历它们并提取一些数据,然后将它们放入最终数组中。我能够做到这一点,但内容是重复的。我尝试阅读有关 reduce 的内容,但不太了解它,并且不确定它是否是正确的解决方案。我还设置了一个 jsfiddle
https://jsfiddle.net/anders_kitson/Lcqn6fgd/
var lineItems = [{
id: 'li_1HyhAZHk5l44uIELgsMWqHqB',
object: 'item',
amount_subtotal: 7500,
amount_total: 7500,
currency: 'cad',
description: 'The Spencer',
price: [Object],
quantity: 1
},
{
id: 'li_1HyhAZHk5l44uIELeNUsiZPu',
object: 'item',
amount_subtotal: 7500,
amount_total: 7500,
currency: 'cad',
description: 'The Gertie',
price: [Object],
quantity: 1
}
]
var arr = [{
id: 'prod_IS1wY1JvSv2CJg',
object: 'product',
active: true,
attributes: [],
created: 1606248785,
description: 'Shelf Set',
images: [
'https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq'
],
livemode: false,
metadata: {},
name: 'The Spencer',
statement_descriptor: null,
type: 'service',
unit_label: null,
updated: 1606248785
},
{
id: 'prod_IS299dMnC13Ezo',
object: 'product',
active: true,
attributes: [],
created: 1606249543,
description: 'Shelf Set',
images: [
'https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe'
],
livemode: false,
metadata: {},
name: 'The Gertie',
statement_descriptor: null,
type: 'service',
unit_label: null,
updated: 1606249543
}
];
let productArr = [];
arr.map((item) => {
lineItems.map((line) => {
productArr.push({
image: item.images[0],
name: item.name,
price: line.amount_total,
});
});
});
console.log(productArr);
这是我得到的输出,您可以在其中看到数组重复值,我知道我已经用这种方式编码了,只是不知道如何修复它。
[{
image: "https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq",
name: "The Spencer",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq",
name: "The Spencer",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}]
更清楚地说,这是我想要的输出
[{
image: "https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq",
name: "The Spencer",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
},
]
我已经尝试过以下评论中的建议
let b
arr.map((item) => {
b = lineItems.map((line) => {
return {
image: item.images[0],
name: item.name,
price: line.amount_total,
};
});
});
但是returns两次都是一样的
[{
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}]
虽然您的问题中没有直接表达,但您似乎希望加入 javascript。我看到的唯一与两者相关的是产品中的 'name' 和订单项中的 'description'。所以做一个循环连接。
下面是一些使用您的示例的示例代码,但只精简了相关内容:
var lineItems = [
{ amount_total: 7500, description: 'The Spencer' },
{ amount_total: 7500, description: 'The Gertie' }
]
var arr = [
{ images: ['Spencer Image 1'], name: 'The Spencer' },
{ images: ['Gertie Image 1'], name: 'The Gertie' }
]
let joined = arr
.flatMap(a => lineItems.map(li => ({a, li})))
.filter(obj => obj.a.name == obj.li.description)
.map(obj => ({
image: obj.a.images[0],
name: obj.a.name,
price: obj.li.amount_total
}));
console.log(joined);
作为循环连接,效率可能不高。进行散列连接要复杂一些。您可以查看我的开发项目的源代码
fluent-data,或者如果你能按照文档直接使用它甚至可能对你有用。
您可以使用单个映射调用并通过索引引用您的第二个 lineItems
数组,前提是您知道这两个数组的长度和顺序相同
const output = arr.map((o, i) => ({
name: o.name,
image: o.images[0],
price: lineItems[i].amount_total}
));
或使用 find()
检索相关对象。
const outputUsingFind = arr.map(o => {
const lineItem = lineItems.find(item => item.description === o.name);
// ** add lineItem valid check here **
return {
name: o.name,
image: o.images[0],
price: lineItem.amount_total};
});
var lineItems = [{amount_subtotal: 7500,amount_total: 700,description: 'The Spencer',},{amount_subtotal: 7500,amount_total: 500,description: 'The Gertie',}];
var arr = [{images: ['spencer image'],name: 'The Spencer',},{images: ['gertie image'],name: 'The Gertie'}];
// since your arrays are ordered the same you can access the second object using
// the index passed from map.
const output = arr.map((o, i) => ({
name: o.name,
image: o.images[0],
price: lineItems[i].amount_total}
));
console.log(output);
// if the two arrays are not in the same order you can use find() to retrieve
// the second object by property (you'll need to check
const outputUsingFind = arr.map(o => {
const lineItem = lineItems.find(item => item.description === o.name);
// ** add lineItem valid check here **
return {
name: o.name,
image: o.images[0],
price: lineItem.amount_total};
});
console.log(outputUsingFind);
.as-console-wrapper { max-height: 100% !important; top: 0; }
我有以下代码和以下数组。我想遍历它们并提取一些数据,然后将它们放入最终数组中。我能够做到这一点,但内容是重复的。我尝试阅读有关 reduce 的内容,但不太了解它,并且不确定它是否是正确的解决方案。我还设置了一个 jsfiddle
https://jsfiddle.net/anders_kitson/Lcqn6fgd/
var lineItems = [{
id: 'li_1HyhAZHk5l44uIELgsMWqHqB',
object: 'item',
amount_subtotal: 7500,
amount_total: 7500,
currency: 'cad',
description: 'The Spencer',
price: [Object],
quantity: 1
},
{
id: 'li_1HyhAZHk5l44uIELeNUsiZPu',
object: 'item',
amount_subtotal: 7500,
amount_total: 7500,
currency: 'cad',
description: 'The Gertie',
price: [Object],
quantity: 1
}
]
var arr = [{
id: 'prod_IS1wY1JvSv2CJg',
object: 'product',
active: true,
attributes: [],
created: 1606248785,
description: 'Shelf Set',
images: [
'https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq'
],
livemode: false,
metadata: {},
name: 'The Spencer',
statement_descriptor: null,
type: 'service',
unit_label: null,
updated: 1606248785
},
{
id: 'prod_IS299dMnC13Ezo',
object: 'product',
active: true,
attributes: [],
created: 1606249543,
description: 'Shelf Set',
images: [
'https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe'
],
livemode: false,
metadata: {},
name: 'The Gertie',
statement_descriptor: null,
type: 'service',
unit_label: null,
updated: 1606249543
}
];
let productArr = [];
arr.map((item) => {
lineItems.map((line) => {
productArr.push({
image: item.images[0],
name: item.name,
price: line.amount_total,
});
});
});
console.log(productArr);
这是我得到的输出,您可以在其中看到数组重复值,我知道我已经用这种方式编码了,只是不知道如何修复它。
[{
image: "https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq",
name: "The Spencer",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq",
name: "The Spencer",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}]
更清楚地说,这是我想要的输出
[{
image: "https://files.stripe.com/links/fl_test_raNEqk9ZhzX3WdQsnvXX4gFq",
name: "The Spencer",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
},
]
我已经尝试过以下评论中的建议
let b
arr.map((item) => {
b = lineItems.map((line) => {
return {
image: item.images[0],
name: item.name,
price: line.amount_total,
};
});
});
但是returns两次都是一样的
[{
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}, {
image: "https://files.stripe.com/links/fl_test_QPbrP76uNn4QadgcUwUnkmbe",
name: "The Gertie",
price: 7500
}]
虽然您的问题中没有直接表达,但您似乎希望加入 javascript。我看到的唯一与两者相关的是产品中的 'name' 和订单项中的 'description'。所以做一个循环连接。
下面是一些使用您的示例的示例代码,但只精简了相关内容:
var lineItems = [
{ amount_total: 7500, description: 'The Spencer' },
{ amount_total: 7500, description: 'The Gertie' }
]
var arr = [
{ images: ['Spencer Image 1'], name: 'The Spencer' },
{ images: ['Gertie Image 1'], name: 'The Gertie' }
]
let joined = arr
.flatMap(a => lineItems.map(li => ({a, li})))
.filter(obj => obj.a.name == obj.li.description)
.map(obj => ({
image: obj.a.images[0],
name: obj.a.name,
price: obj.li.amount_total
}));
console.log(joined);
作为循环连接,效率可能不高。进行散列连接要复杂一些。您可以查看我的开发项目的源代码 fluent-data,或者如果你能按照文档直接使用它甚至可能对你有用。
您可以使用单个映射调用并通过索引引用您的第二个 lineItems
数组,前提是您知道这两个数组的长度和顺序相同
const output = arr.map((o, i) => ({
name: o.name,
image: o.images[0],
price: lineItems[i].amount_total}
));
或使用 find()
检索相关对象。
const outputUsingFind = arr.map(o => {
const lineItem = lineItems.find(item => item.description === o.name);
// ** add lineItem valid check here **
return {
name: o.name,
image: o.images[0],
price: lineItem.amount_total};
});
var lineItems = [{amount_subtotal: 7500,amount_total: 700,description: 'The Spencer',},{amount_subtotal: 7500,amount_total: 500,description: 'The Gertie',}];
var arr = [{images: ['spencer image'],name: 'The Spencer',},{images: ['gertie image'],name: 'The Gertie'}];
// since your arrays are ordered the same you can access the second object using
// the index passed from map.
const output = arr.map((o, i) => ({
name: o.name,
image: o.images[0],
price: lineItems[i].amount_total}
));
console.log(output);
// if the two arrays are not in the same order you can use find() to retrieve
// the second object by property (you'll need to check
const outputUsingFind = arr.map(o => {
const lineItem = lineItems.find(item => item.description === o.name);
// ** add lineItem valid check here **
return {
name: o.name,
image: o.images[0],
price: lineItem.amount_total};
});
console.log(outputUsingFind);
.as-console-wrapper { max-height: 100% !important; top: 0; }