Oracle SUM( TO_NUMBER( REGEXP_SUBSTR 带小数

Question

我有这样的查询

SELECT SUM( TO_NUMBER( REGEXP_SUBSTR( '2,0,0,0,0,0,8.36,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0', '\d+', 1, LEVEL ) ) ) AS SUM_TOTAL
FROM   DUAL
CONNECT BY LEVEL <= REGEXP_COUNT( '2,0,0,0,0,0,8.36,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0', '\d+' );

我的结果是 46，小数 (8.36) 被计算为单个数字，例如 (2 + 8 + 36) = 46。

我正在努力获得结果 (2 + 8.36) = 10.36

有可能得到这个结果吗？

提前致谢

Answer 1

您需要跳过逗号而不是 '\d+'。

使用'[^,]+'

所以你的查询将是

我有这样的查询

SELECT SUM( TO_NUMBER( REGEXP_SUBSTR( '2,0,0,0,0,0,8.36,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0', '[^,]+', 1, LEVEL ) ) ) AS SUM_TOTAL
FROM   DUAL
CONNECT BY LEVEL <= REGEXP_COUNT( '2,0,0,0,0,0,8.36,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0', ',' ) + 1;

Answer 2

如果您确定您的字符串是数字的逗号分隔列表，包括十进制数、负数、指数计数法等，可能被空格包围，您可以使用 [^,]+ 而不是 \d+ 修改查询（在两个地方）。这一次选择所有连续非逗号字符的子串，而不是一次选择所有连续数字的子串。

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