Java: 使用静态方法在 Main 之外的方法中调用对象
Java: Calling Object in Method Outside of Main with Static Methods
应该很容易解决,但我想知道如何使用在 main 中创建的对象。我试着说 Human h;在 main (或任何其他方法)之外,所以我可以在其他方法中调用它,但是因为我使用的是静态方法,所以我不能使用 h.现在使用此代码,java 告诉我找不到 h(在人工滚动方法中。)
import java.util.Scanner;
class Main
{
// static Human h;
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
Computer c = new Computer();
Human h = new Human();
System.out.println("Let's play PIG");
System.out.println("What is your name");
String name = scan.nextLine();
System.out.println("Hello" + " " + name + " " + "you can go first");
startGame(h, name);
}
public static void startGame(Human h, String name)
{
Scanner scan = new Scanner(System.in);
System.out.println("Press r to start your roll");
String rresponse = scan.nextLine();
if(!rresponse.equalsIgnoreCase("R"))
{
System.out.println("Try again");
startGame(h, name);
}
if(rresponse.equalsIgnoreCase("R"))
{
System.out.println("You pressed r, lets roll");
humanRoll(h, name);
}
}
public static void humanRoll(Human h, String name)
{
if(h.getRollNumh()==1)
{
System.out.println(name + " " + "you got a " + h.getRollNumh());
System.out.println("You got a score of" + h.getHumanTurnScore() + "this turn");
System.out.println("Here is your current overall score" + h.getHumanOverallScore());
System.out.println("Your rolled a one, now its the Computers' turn");
switchHuman();
}
}
}
如果您需要查看 Human class 以提供上下文,我可以快速响应并添加它,但它只是实例变量、默认构造函数、重载构造函数、访问器方法和增变器方法。
如果你希望Human h是静态的(在你的程序中只有一个),那么你可以这样定义它:
static Human h;
public static void main(...) {
...
您可以将 Human 作为方法参数传递给 startGame 和 humanRoll
将它们定义为
public static void startGame(Human human)
public static void humanRoll(Human human)
然后,在 main 中,调用 startGame(h)
.
看看这是否有效...
import java.util.Scanner;
class Main {
//tried to put Human h; up here but didn't work due to static methods
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
Computer c = new Computer();
Human h = new Human();
System.out.println("Let's play PIG");
System.out.println("What is your name");
String name = scan.nextLine();
System.out.println("Hello" + " " + name + " " + "you can go first");
startGame(h);
}
public static void startGame(Human h) {
Scanner scan = new Scanner(System.in);
System.out.println("Press r to start your roll");
String rresponse = scan.nextLine();
if (!rresponse.equalsIgnoreCase("R"))
{
System.out.println("Try again");
startGame(h);
}
if (rresponse.equalsIgnoreCase("R"))
{
System.out.println("You pressed r, lets roll");
humanRoll(h);
}
}
public static void humanRoll(Human h)
{
//RollNumh is just the dice number that the player rolled
if (h.getRollNumh() == 1)
{
System.out.println(name + " " + "you got a " + h.getRollNumh);
System.out.println("You got a score of" + h.getHumanTurnScore() + "this turn");
System.out.println("Here is your current overall score" + h.getOverallHumanOverallScore());
System.out.println("Your rolled a one, now its the Computers' turn");
switchHuman();
}
}
}
在Java中,在函数内部声明的变量只能在函数内部使用。我们说变量的作用域只在函数内。
修复:您可以将变量 h 作为参数传递给其他函数。
应该很容易解决,但我想知道如何使用在 main 中创建的对象。我试着说 Human h;在 main (或任何其他方法)之外,所以我可以在其他方法中调用它,但是因为我使用的是静态方法,所以我不能使用 h.现在使用此代码,java 告诉我找不到 h(在人工滚动方法中。)
import java.util.Scanner;
class Main
{
// static Human h;
public static void main(String[] args)
{
Scanner scan = new Scanner(System.in);
Computer c = new Computer();
Human h = new Human();
System.out.println("Let's play PIG");
System.out.println("What is your name");
String name = scan.nextLine();
System.out.println("Hello" + " " + name + " " + "you can go first");
startGame(h, name);
}
public static void startGame(Human h, String name)
{
Scanner scan = new Scanner(System.in);
System.out.println("Press r to start your roll");
String rresponse = scan.nextLine();
if(!rresponse.equalsIgnoreCase("R"))
{
System.out.println("Try again");
startGame(h, name);
}
if(rresponse.equalsIgnoreCase("R"))
{
System.out.println("You pressed r, lets roll");
humanRoll(h, name);
}
}
public static void humanRoll(Human h, String name)
{
if(h.getRollNumh()==1)
{
System.out.println(name + " " + "you got a " + h.getRollNumh());
System.out.println("You got a score of" + h.getHumanTurnScore() + "this turn");
System.out.println("Here is your current overall score" + h.getHumanOverallScore());
System.out.println("Your rolled a one, now its the Computers' turn");
switchHuman();
}
}
}
如果您需要查看 Human class 以提供上下文,我可以快速响应并添加它,但它只是实例变量、默认构造函数、重载构造函数、访问器方法和增变器方法。
如果你希望Human h是静态的(在你的程序中只有一个),那么你可以这样定义它:
static Human h;
public static void main(...) {
...
您可以将 Human 作为方法参数传递给 startGame 和 humanRoll 将它们定义为
public static void startGame(Human human)
public static void humanRoll(Human human)
然后,在 main 中,调用 startGame(h)
.
看看这是否有效...
import java.util.Scanner;
class Main {
//tried to put Human h; up here but didn't work due to static methods
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
Computer c = new Computer();
Human h = new Human();
System.out.println("Let's play PIG");
System.out.println("What is your name");
String name = scan.nextLine();
System.out.println("Hello" + " " + name + " " + "you can go first");
startGame(h);
}
public static void startGame(Human h) {
Scanner scan = new Scanner(System.in);
System.out.println("Press r to start your roll");
String rresponse = scan.nextLine();
if (!rresponse.equalsIgnoreCase("R"))
{
System.out.println("Try again");
startGame(h);
}
if (rresponse.equalsIgnoreCase("R"))
{
System.out.println("You pressed r, lets roll");
humanRoll(h);
}
}
public static void humanRoll(Human h)
{
//RollNumh is just the dice number that the player rolled
if (h.getRollNumh() == 1)
{
System.out.println(name + " " + "you got a " + h.getRollNumh);
System.out.println("You got a score of" + h.getHumanTurnScore() + "this turn");
System.out.println("Here is your current overall score" + h.getOverallHumanOverallScore());
System.out.println("Your rolled a one, now its the Computers' turn");
switchHuman();
}
}
}
在Java中,在函数内部声明的变量只能在函数内部使用。我们说变量的作用域只在函数内。
修复:您可以将变量 h 作为参数传递给其他函数。