Sapper 在点击 link 时没有重新加载数据
Sapper is not reloading data when hitting link
我正在使用 sapper 构建一个站点并从 API 请求数据。到现在为止一直很顺利。
当我从 site.com/title/id1 转到 site.com/title/id2 时,在我手动刷新之前不会加载新信息。有什么想法吗?
import { stores, goto } from "@sapper/app";
import Card from "../_titlecard.svelte";
const { page } = stores();
const { slug } = $page.params;
import { onMount } from "svelte";
let looper = [];
let artistName = "";
let titleName = "";
let dvdCover = "";
let titleCover = "";
let genre = "";
let tracks = [];
onMount(async () => {
const res = await fetch(`https://.com/api/title/${slug}`);
const data = await res.json();
artistName = data.artistName;
titleName = data.name;
dvdCover = data.graphics.dvd;
titleCover = data.graphics.landscape;
genre = data.genre;
tracks = data.tracks.length;
const res2 = await fetch(`https://.com/api/artists/all`);
const data2 = await res2.json();
let moreTitles = [];
const more = data2.map((x) => {
if (x.titles.length > 0 && x.genre === genre) {
looper.push(x.titles[0]);
looper = moreTitles;
}
});
});
然后我在 html
中有这个
{#each looper.slice(0, 4) as item, i}
<Card imgurl={item.graphics.dvd} concert={item.name} id={item.id} />
{/each}
如果导航导致使用相同的页面组件,则页面组件不会卸载并再次安装,因此您的 onMount
只会 运行 一次与第一个 id
.
您可以使用 reactive statement 来确保每次 $page.params.slug
更改时您都 运行 所需的代码。
例子
import { stores, goto } from "@sapper/app";
import Card from "../_titlecard.svelte";
const { page } = stores();
let looper = [];
let artistName = "";
let titleName = "";
let dvdCover = "";
let titleCover = "";
let genre = "";
let tracks = [];
$: (async () => {
const { slug } = $page.params;
const res = await fetch(`https://.com/api/title/${slug}`);
const data = await res.json();
artistName = data.artistName;
titleName = data.name;
dvdCover = data.graphics.dvd;
titleCover = data.graphics.landscape;
genre = data.genre;
tracks = data.tracks.length;
const res2 = await fetch(`https://.com/api/artists/all`);
const data2 = await res2.json();
let moreTitles = [];
data2.forEach((x) => {
if (x.titles.length > 0 && x.genre === genre) {
moreTitles.push(x.titles[0]);
}
});
looper = moreTitles;
})();
我正在使用 sapper 构建一个站点并从 API 请求数据。到现在为止一直很顺利。
当我从 site.com/title/id1 转到 site.com/title/id2 时,在我手动刷新之前不会加载新信息。有什么想法吗?
import { stores, goto } from "@sapper/app";
import Card from "../_titlecard.svelte";
const { page } = stores();
const { slug } = $page.params;
import { onMount } from "svelte";
let looper = [];
let artistName = "";
let titleName = "";
let dvdCover = "";
let titleCover = "";
let genre = "";
let tracks = [];
onMount(async () => {
const res = await fetch(`https://.com/api/title/${slug}`);
const data = await res.json();
artistName = data.artistName;
titleName = data.name;
dvdCover = data.graphics.dvd;
titleCover = data.graphics.landscape;
genre = data.genre;
tracks = data.tracks.length;
const res2 = await fetch(`https://.com/api/artists/all`);
const data2 = await res2.json();
let moreTitles = [];
const more = data2.map((x) => {
if (x.titles.length > 0 && x.genre === genre) {
looper.push(x.titles[0]);
looper = moreTitles;
}
});
});
然后我在 html
中有这个{#each looper.slice(0, 4) as item, i}
<Card imgurl={item.graphics.dvd} concert={item.name} id={item.id} />
{/each}
如果导航导致使用相同的页面组件,则页面组件不会卸载并再次安装,因此您的 onMount
只会 运行 一次与第一个 id
.
您可以使用 reactive statement 来确保每次 $page.params.slug
更改时您都 运行 所需的代码。
例子
import { stores, goto } from "@sapper/app";
import Card from "../_titlecard.svelte";
const { page } = stores();
let looper = [];
let artistName = "";
let titleName = "";
let dvdCover = "";
let titleCover = "";
let genre = "";
let tracks = [];
$: (async () => {
const { slug } = $page.params;
const res = await fetch(`https://.com/api/title/${slug}`);
const data = await res.json();
artistName = data.artistName;
titleName = data.name;
dvdCover = data.graphics.dvd;
titleCover = data.graphics.landscape;
genre = data.genre;
tracks = data.tracks.length;
const res2 = await fetch(`https://.com/api/artists/all`);
const data2 = await res2.json();
let moreTitles = [];
data2.forEach((x) => {
if (x.titles.length > 0 && x.genre === genre) {
moreTitles.push(x.titles[0]);
}
});
looper = moreTitles;
})();