是否可以使用spookyjs从casperjs范围内的节点范围调用评估函数？

Question

我试图将一个外部函数传递给spooky，但是当我调用它时，返回值是'undefined'。这是我的代码：

        var eval_func = function(){
           return 123;
        };
        console.log('Outside spooky: ' + eval_func());
        var spooky = new Spooky({
            child: {
                transport: 'http',
            },
            casper: {
                logLevel: 'error',
            }
        }, function (err) {
            if (err) {
                e = new Error('Failed to initialize SpookyJS');
                e.details = err;
                throw e;
            }

            spooky.start('http://google.com/',[{
                eval_func:eval_func,
            },function(){
                console.log('Inside spooky: ' + eval_func());
            }]);
            spooky.run();
        });

        spooky.on('console', function (line) {
            console.log(line);
        });
    });

输出为：

Outside spooky: 123

我得到 "ReferenceError: Can't find variable: eval_func"。是否可以在没有任何 ReferenceError 的情况下执行此操作？

Answer 1

好的，我找到了解决这个问题的好方法。我复制了函数字符串，然后在 casperjs 范围内重新生成它。

        eval_func = function(){
            return 123;
        }
        console.log('Outside spooky: ' + eval_func());
        var spooky = new Spooky({
            child: {
                transport: 'http',
            },
            casper: {
                logLevel: 'error',
            }
        }, function (err) {
            if (err) {
                e = new Error('Failed to initialize SpookyJS');
                e.details = err;
                throw e;
            }
            eval_func_str = eval_func.toString();

            spooky.start('http://google.com/',[{
                eval_func_str:eval_func_str,
            },function(){
                eval("eval_func=" + eval_func_str);
                console.log('Inside spooky: ' + eval_func());
            }]);

            spooky.run();
        });

        spooky.on('console', function (line) {
            console.log(line);
        });

Answer 2

如果需要函数的值，传入返回值：

var Spooky;
try {
  Spooky = require('spooky');
} catch (e) {
  Spooky = require('../lib/spooky');
}
var eval_func = function() {
  return 123;
};
console.log('Outside spooky: ' + eval_func());
var spooky = new Spooky({
  child: {
    transport: 'http',
  },
  casper: {
    logLevel: 'error',
  }
}, function(err) {
  if (err) {
    e = new Error('Failed to initialize SpookyJS');
    e.details = err;
    throw e;
  }

  spooky.start('http://google.com/', [{
    eval_func: eval_func(),
  }, function() {
    console.log('Inside spooky: ' + eval_func);
  }]);
  spooky.run();
});

spooky.on('console', function(line) {
  console.log(line);
});

如果您需要从 SpookyJS 调用函数，请尝试 "emit":

var Spooky;
try {
  Spooky = require('spooky');
} catch (e) {
  Spooky = require('../lib/spooky');
}
var eval_func = function() {
  return 123;
};
console.log('Outside spooky: ' + eval_func());
var spooky = new Spooky({
  child: {
    transport: 'http',
  },
  casper: {
    logLevel: 'error',
  }
}, function(err) {
  if (err) {
    e = new Error('Failed to initialize SpookyJS');
    e.details = err;
    throw e;
  }

  spooky.start('http://google.com/', function() {
    var spookyScope = 42;
    this.emit('eval_func_call', "Another value from within Spooky is " + 42);
  });

  spooky.on('eval_func_call', function(spookyValue) {
    console.log("Calling eval_func inside Spooky", eval_func());
    console.log("and...", spookyValue)
  });

  spooky.run();
});

spooky.on('console', function(line) {
  console.log(line);
});

这给你：

Outside spooky: 123
Calling eval_func inside Spooky 123
and... Another value from within Spooky is 42

是否可以使用spookyjs从casperjs范围内的节点范围调用评估函数？

is it possible to call evaluation function from node scope in casperjs scope using spookyjs?

javascript

node.js

phantomjs

casperjs

spookyjs