在声明部分分配多个值

Assign multiple values in declaration part

我需要通过提供多个声明值来实现结果。怎么做到的?

DECLARE @ID INT

SET @ID = 1   --instead I need to provide multiple values like @ID = 1,2,3

SELECT C.Name, C.EmployeeID 
FROM Cases c
WHERE C.EmployeeID = @ID

Table

Name   |    ID
-------+---------
A           1
B           2
C           3
D           4
E           5
F           6

结果应该是:

A           1
B           2
C           3

一种方法是使用 table 变量:

DECLARE @IDs TABLE(ID INT);
INSERT INTO @IDs VALUES(1),(2),(3);

SELECT C.Name, C.EmployeeID 
FROM dbo.Cases AS c
WHERE C.EmployeeID IN(SELECT ID FROM @IDs);

一个非常简单的方法是使用 XML 数据类型。

DECLARE @ids xml = '<ids><id>1</id><id>2</id><id>3</id></ids>';

SELECT 
    C.[Name],
    C.EmployeeID 
FROM Cases c 
WHERE C.EmployeeID IN (

    SELECT x.f.value( '.', 'int' ) FROM @ids.nodes ( '//ids/id' ) x( f )

);