取消选中 jqxGrid 中列的所有复选框

To uncheck all checkboxes of an column in jqxGrid

我使用 jqxGrid 构建了小型 table。第一列包含如下复选框:

预期结果:

  1. 点击 全部取消选中 ,需要像这样取消选中所有这些复选框:

  1. 点击删除需要获取复选框选中行的数据。

HTML:

<div id='travelGrid'></div>
<br>
<button id="unselect">Unselect All</button>

删除

JS:

$( document ).ready(function() {
var travelGridSource = {
      localdata: [],
      datafields: [
           { name: 'isSelected', type: 'bool' },
           { name: 'Zipcode', type: 'number' },
           { name: 'TravelFee', type: 'number' }
      ],
      datatype: "array"
}

 
var travelFees = [
                { "isSelected": "true", "Zipcode": "001", "TravelFee": "25"},
                { "isSelected": "true", "Zipcode": "002", "TravelFee": "75"},
                { "isSelected": "false", "Zipcode": "003", "TravelFee": "75"},
                { "isSelected": "true", "Zipcode": "004", "TravelFee": "75" },
                { "isSelected": "false", "Zipcode": "004", "TravelFee": "75" }
 ];
 
 travelGridSource.localdata = travelFees;
 
                 $("#travelGrid").jqxGrid({
                    width: '100%',
                    height: '20%',
                    rowsheight: 29,
                    columnsheight: 29,
                    source: new $.jqx.dataAdapter(travelGridSource),
                    sortable: true,
                    columnsresize: true,
                    columnsmenu: false,
                    showsortcolumnbackground: false,
                    enablehover: false,
                    selectionmode: 'none',
                    scrollmode: 'logical',
                    theme: 'light',
                    rowdetails: true,
                    editable: true,
                    showrowdetailscolumn: false,
                    columns: [
                        { text: '', datafield: 'isSelected', width: '7%', align: 'center', columntype: 'checkbox', cellsalign: 'center', 'editable': true  },
                        { text: 'Zip', datafield: 'Zipcode', width: '15%', align: 'center', cellsalign: 'center', 'editable': false  },
                        { text: 'Travel Fee', datafield: 'TravelFee', width: '20%', align: 'center', cellsalign: 'center', cellsformat: 'c2'}
                    ]
                });
 });
 
 
 $('#unselect').click(function(){
    // Do something here
 });

 $('#remove').click(function(){
    // Do something here
 });

浏览了很多和文档,但没有用。无法附加 fiddle link,所以粘贴 fiddle URL作为代码:

 https://jsfiddle.net/75zrfko0/25/

首先,由于数据集的本地范围,您必须在 jQuery 文档的范围内处理取消选择的点击事件。

$(document).ready(function(){
   //unselect onclick event listener
})

然后单击该按钮,您必须更新要从中添加复选框标志的本地数据集,最后必须更新您获取的 jqxGrid 中的源。

    $('#unselect').click(function(){
    // Do something here
     travelFees = travelFees.map((obj) => {
        obj.isSelected = "false";
            return {...obj};
     })
     travelGridSource.localdata = travelFees;
     $("#travelGrid").jqxGrid({source: new $.jqx.dataAdapter(travelGridSource)});
 });

我还没有完全完成 JQXWiget 的 API 但是可以有一种更新本地数据集的方法请按照下面的 link,

  1. https://www.jqwidgets.com/jquery-widgets-demo/demos/jqxgrid/index.htm#demos/jqxgrid/checkboxcolumn.htm