减少没有链接的 CROSS JOIN + LEFT JOIN 的行数

Reducing row count of CROSS JOIN + LEFT JOIN where there is no linkage

我已经为此苦苦挣扎了一段时间。我有一个SQLFiddle with the same approximate contents of this question.

我有三个 table,itemsprofiles,以及链接 table,posts,前两个 [=34] 的键=]s,带有示例数据的模式:

create table items ( 
  item_id int unsigned primary key auto_increment,
  title varchar(255)
);

insert into items (item_id, title) VALUES(1, 'Item One');
insert into items (item_id, title) VALUES(2, 'Item Two');
insert into items (item_id, title) VALUES(3, 'Item Three');
insert into items (item_id, title) VALUES(4, 'Item Four');
insert into items (item_id, title) VALUES(5, 'Item Five');

create table profiles (
  profile_id int unsigned primary key auto_increment,
  profile_name varchar(255)
);

insert into profiles (profile_id, profile_name) VALUES(1, 'Bob');
insert into profiles (profile_id, profile_name) VALUES(1, 'Mark');
insert into profiles (profile_id, profile_name) VALUES(1, 'Nancy');

create table posts (
  post_id int unsigned primary key auto_increment,
  item_id int unsigned, -- Relates to items.item_id
  profile_id int unsigned, -- Relates to profile.profile_id,
  post_date DATETIME
);

insert into posts (item_id, profile_id, post_date) values(1, 1, NOW());
insert into posts (item_id, profile_id, post_date) values(2, 2, NOW());
insert into posts (item_id, profile_id, post_date) values(2, 2, NOW());

我正在使用以下查询生成几乎正确的结果:

SELECT 
  `items`.`item_id`,
  `items`.`title`,
  `profiles`.`profile_id`,
  `profiles`.`profile_name`,
  `posts`.`post_id`, 
  `posts`.`post_date`
  FROM `items` 
  CROSS JOIN `profiles`
  LEFT JOIN  `posts` ON `items`.`item_id` = `posts`.`item_id`
    AND `posts`.`profile_id` = `profiles`.`profile_id`;

对于我的特定应用程序,这是次优的。我得到了很多我的特定实现不需要的 'extra' 行。最终结果看起来像这样:

+------------|------------|---------|-----------+
| Item Name  | Profile ID | Post ID | Post Date |
+------------+------------+---------+-----------+
| Item One   | 1          | 1       | 2015-...  | -- Bob Posted this
| Item One   | 2          | NULL    | NULL      | -- No one else did
| Item One   | 3          | NULL    | NULL      |
| Item Two   | 1          | 2       | 2015-...  | -- Bob posted this
| Item Two   | 2          | 3       | 2015-...  | -- So did mark
| Item Two   | 3          | NULL    | NULL      | -- Nancy didn't
| Item Three | 1          | NULL    | NULL      | 
| Item Three | 2          | NULL    | NULL      |
| Item Three | 3          | 4       | 2015-...  | -- Only nancy posted #3
| Item Four  | 1          | NULL    | NULL      | -- No one posted #4
| Item Four  | 2          | NULL    | NULL      |
| Item Four  | 3          | NULL    | NULL      | 
| Item Five  | 1          | NULL    | NULL      | -- No one posted #5
| Item Five  | 2          | NULL    | NULL      |
| Item Five  | 3          | NULL    | NULL      | 
+------------+------------+---------+-----------+

这完全按照我的要求进行 - 每个项目都返回三次(对应于配置文件计数)。然而,如果在第 4 项和第 5 项没有链接的情况下,它们只返回一次并带有 NULL profile_id,将是理想的,如下所示:

+------------|------------|---------|-----------+
| Item Name  | Profile ID | Post ID | Post Date |
+------------+------------+---------+-----------+
| Item One   | 1          | 1       | 2015-...  | -- Bob Posted this
| Item One   | 2          | NULL    | NULL      | -- No one else did
| Item One   | 3          | NULL    | NULL      |
| Item Two   | 1          | 2       | 2015-...  | -- Bob posted this
| Item Two   | 2          | 3       | 2015-...  | -- So did mark
| Item Two   | 3          | NULL    | NULL      | -- Nancy didn't
| Item Three | 1          | NULL    | NULL      | 
| Item Three | 2          | NULL    | NULL      |
| Item Three | 3          | 4       | 2015-...  | -- Nancy posted #3
| Item Four  | NULL       | NULL    | NULL      | -- **No one posted #3 and #4
| Item Five  | NULL       | NULL    | NULL      | -- Only need #3 and #4 once**
+------------+------------+---------+-----------+

虽然在这个例子中这只意味着少了 4 行,但在我的实际应用程序中,有很多项目,但配置文件和帖子并不多。所以这个小改动可以显着减少服务器端语言处理。

任何人都可以指出正确的方向,只在我有某种类型的链接的地方限制交叉连接吗?

SELECT  `items`.`item_id`,
        `items`.`title`,
        `profiles`.`profile_id`,
        `profiles`.`profile_name`,
        `posts`.`post_id`, 
        `posts`.`post_date`
FROM    `items` 
LEFT JOIN
        `profiles`
ON      EXISTS
        (
        SELECT  NULL
        FROM    `posts`
        WHERE   `posts`.`item_id` = `items`.`item_id`
        )
LEFT JOIN
        `posts`
ON      `items`.`item_id` = `posts`.`item_id`
        AND `posts`.`profile_id` = `profiles`.`profile_id`
ORDER BY
        `items`.`item_id`, `profiles`.`profile_id`

http://sqlfiddle.com/#!9/c81b1/41