通过 Golang 中的步骤函数调用 AWS lambda 函数
Invoking an AWS lambda function through step functions in Golang
我有一个调用用 Golang 编写的 lambda 函数的 AWS 步骤函数。出于某种原因,lambda 函数似乎无法读取 step 函数的输入。
lambda 函数 -
package main
import (
"fmt"
"github.com/aws/aws-lambda-go/lambda"
)
type InEvent struct {
Name string `json:"name"`
}
type OutEvent struct {
Greeting string `json:"greeting"`
}
func HandleRequest(name InEvent) (OutEvent, error) {
var result OutEvent
result.Greeting = fmt.Sprintf("Hello %s!", name.Name)
return result, nil
}
func main() {
lambda.Start(HandleRequest)
}
阶跃函数-
{
"Comment": "A Hello World example of the Amazon States Language using Pass states",
"StartAt": "Invoke Lambda function",
"States": {
"Invoke Lambda function": {
"Type": "Task",
"Resource": "arn:aws:states:::lambda:invoke",
"Parameters": {
"FunctionName": "arn:aws:lambda:us-west-1:301438421794:function:SF1_1:$LATEST",
"Payload": {
"Input.$": "$"
}
},
"End": true
}
}
}
步进函数的输入-
{
"name": "ABCDE"
}
步进函数的输出-
{
"ExecutedVersion": "$LATEST",
"Payload": {
"greeting": "Hello !"
},
"SdkHttpMetadata": {
"AllHttpHeaders": {
"X-Amz-Executed-Version": [
"$LATEST"
],
"x-amzn-Remapped-Content-Length": [
"0"
],
"Connection": [
"keep-alive"
],
"x-amzn-RequestId": [
"5f297331-8b1a-49a0-9ad9-17a78ec1cfd0"
],
"Content-Length": [
"22"
],
"Date": [
"Fri, 25 Dec 2020 19:58:20 GMT"
],
"X-Amzn-Trace-Id": [
"root=1-5fe6445c-5cb6860d2559230940506a2f;sampled=0"
],
"Content-Type": [
"application/json"
]
},
"HttpHeaders": {
"Connection": "keep-alive",
"Content-Length": "22",
"Content-Type": "application/json",
"Date": "Fri, 25 Dec 2020 19:58:20 GMT",
"X-Amz-Executed-Version": "$LATEST",
"x-amzn-Remapped-Content-Length": "0",
"x-amzn-RequestId": "5f297331-8b1a-49a0-9ad9-17a78ec1cfd0",
"X-Amzn-Trace-Id": "root=1-5fe6445c-5cb6860d2559230940506a2f;sampled=0"
},
"HttpStatusCode": 200
},
"SdkResponseMetadata": {
"RequestId": "5f297331-8b1a-49a0-9ad9-17a78ec1cfd0"
},
"StatusCode": 200
}
我希望 Output.Payload.greeting 是“你好 ABCDE!”但 Output.Payload.greeting 是“你好!”
这里出了什么问题?为什么 lambda 函数中的名称变量没有正确存储输入?为什么“ABCDE”在lambda函数中变成空字符串?
当我直接在 lambda 控制台上测试 lambda 函数而不使用步骤函数时,一切正常。
您的状态机定义中的 Payload
部分正在调整传递给 Lambda 的输入:
"Payload": {
"Input.$": "$"
}
因此 Lambda 的实际输入将是:
{
Input:
{
name: 'ABCDE'
}
}
因此您需要在您的 Golang 代码中考虑这一点,或者更改状态机定义中的 Payload
部分。
分享代码和示例时要小心,因为您的帐户 ID 也会被暴露
下面是你的 golang 代码的工作状态机
{
"Comment": "A Hello World example of the Amazon States Language using Pass states",
"StartAt": "Invoke Lambda function",
"States": {
"Invoke Lambda function": {
"Type": "Task",
"Resource": "arn:aws:states:::lambda:invoke",
"Parameters": {
"FunctionName": "arn:aws:lambda:us-east-1:301438421794:function:testfunction",
"Payload": {
"name.$": "$.name"
}
},
"ResultPath": "$.lambdaOutput",
"End": true
}
}
}
产生如下输出:
{
"name": "suresh",
"lambdaOutput": {
"ExecutedVersion": "$LATEST",
"Payload": {
"greeting": "Hello suresh!"
},
"SdkHttpMetadata": {
....
}
您可以通过这样修改来进一步分割输出
"OutputPath": "$.lambdaOutput.Payload",
这将为您提供准确的输出
{
"greeting": "Hello suresh!"
}
看看here。这是我可以推荐的最好的资源,用于开始使用步进函数。
对于处理函数之间的数据,keep this handy. For handling the inputs and outputs this 也非常有用。
我有一个调用用 Golang 编写的 lambda 函数的 AWS 步骤函数。出于某种原因,lambda 函数似乎无法读取 step 函数的输入。
lambda 函数 -
package main
import (
"fmt"
"github.com/aws/aws-lambda-go/lambda"
)
type InEvent struct {
Name string `json:"name"`
}
type OutEvent struct {
Greeting string `json:"greeting"`
}
func HandleRequest(name InEvent) (OutEvent, error) {
var result OutEvent
result.Greeting = fmt.Sprintf("Hello %s!", name.Name)
return result, nil
}
func main() {
lambda.Start(HandleRequest)
}
阶跃函数-
{
"Comment": "A Hello World example of the Amazon States Language using Pass states",
"StartAt": "Invoke Lambda function",
"States": {
"Invoke Lambda function": {
"Type": "Task",
"Resource": "arn:aws:states:::lambda:invoke",
"Parameters": {
"FunctionName": "arn:aws:lambda:us-west-1:301438421794:function:SF1_1:$LATEST",
"Payload": {
"Input.$": "$"
}
},
"End": true
}
}
}
步进函数的输入-
{
"name": "ABCDE"
}
步进函数的输出-
{
"ExecutedVersion": "$LATEST",
"Payload": {
"greeting": "Hello !"
},
"SdkHttpMetadata": {
"AllHttpHeaders": {
"X-Amz-Executed-Version": [
"$LATEST"
],
"x-amzn-Remapped-Content-Length": [
"0"
],
"Connection": [
"keep-alive"
],
"x-amzn-RequestId": [
"5f297331-8b1a-49a0-9ad9-17a78ec1cfd0"
],
"Content-Length": [
"22"
],
"Date": [
"Fri, 25 Dec 2020 19:58:20 GMT"
],
"X-Amzn-Trace-Id": [
"root=1-5fe6445c-5cb6860d2559230940506a2f;sampled=0"
],
"Content-Type": [
"application/json"
]
},
"HttpHeaders": {
"Connection": "keep-alive",
"Content-Length": "22",
"Content-Type": "application/json",
"Date": "Fri, 25 Dec 2020 19:58:20 GMT",
"X-Amz-Executed-Version": "$LATEST",
"x-amzn-Remapped-Content-Length": "0",
"x-amzn-RequestId": "5f297331-8b1a-49a0-9ad9-17a78ec1cfd0",
"X-Amzn-Trace-Id": "root=1-5fe6445c-5cb6860d2559230940506a2f;sampled=0"
},
"HttpStatusCode": 200
},
"SdkResponseMetadata": {
"RequestId": "5f297331-8b1a-49a0-9ad9-17a78ec1cfd0"
},
"StatusCode": 200
}
我希望 Output.Payload.greeting 是“你好 ABCDE!”但 Output.Payload.greeting 是“你好!”
这里出了什么问题?为什么 lambda 函数中的名称变量没有正确存储输入?为什么“ABCDE”在lambda函数中变成空字符串?
当我直接在 lambda 控制台上测试 lambda 函数而不使用步骤函数时,一切正常。
您的状态机定义中的 Payload
部分正在调整传递给 Lambda 的输入:
"Payload": {
"Input.$": "$"
}
因此 Lambda 的实际输入将是:
{
Input:
{
name: 'ABCDE'
}
}
因此您需要在您的 Golang 代码中考虑这一点,或者更改状态机定义中的 Payload
部分。
分享代码和示例时要小心,因为您的帐户 ID 也会被暴露
下面是你的 golang 代码的工作状态机
{
"Comment": "A Hello World example of the Amazon States Language using Pass states",
"StartAt": "Invoke Lambda function",
"States": {
"Invoke Lambda function": {
"Type": "Task",
"Resource": "arn:aws:states:::lambda:invoke",
"Parameters": {
"FunctionName": "arn:aws:lambda:us-east-1:301438421794:function:testfunction",
"Payload": {
"name.$": "$.name"
}
},
"ResultPath": "$.lambdaOutput",
"End": true
}
}
}
产生如下输出:
{
"name": "suresh",
"lambdaOutput": {
"ExecutedVersion": "$LATEST",
"Payload": {
"greeting": "Hello suresh!"
},
"SdkHttpMetadata": {
....
}
您可以通过这样修改来进一步分割输出
"OutputPath": "$.lambdaOutput.Payload",
这将为您提供准确的输出
{
"greeting": "Hello suresh!"
}
看看here。这是我可以推荐的最好的资源,用于开始使用步进函数。
对于处理函数之间的数据,keep this handy. For handling the inputs and outputs this 也非常有用。