在 python 中练习循环时遇到问题

Having problems with practicing loop in python

import time
import random
import math

start = 1
stop = 10

for i in range(start, stop):
    time.sleep(1)
    print("\ni = {}".format(i), end = "")
    count = 3 + random.randint(1,5)
    print(", count = {}".format(count))
    nums = []
    while len(nums) < count:
        for j in range(count):
            time.sleep(0.3)
            try:
                num = random.randint(-10,100)
                log = round(math.log(num),1)
            except:
                time.sleep(2)
                print("\nagain")
                break
            nums.append(log)
            print("\rnums = {}".format(nums), end = "")

我想要做的是为每次迭代 i 提供一个随机整数 count,然后使用 while 循环将 num 的日志附加到 nums 直到 nums 的长度等于 count。这里num是-10到100之间的随机整数,如果num给定为0或以下,我想从for i in range(start, stop):的最开始重新开始循环,也就是time.sleep(1),这样我就可以指定 new count 和 make new nums.

于是我执行了上面的代码,它又从while len(nums) < count:开始循环了。

例如,我期望的是这样的

i = 1, count = 7
nums = [4.2, 4.4, 2.9, 4.4]
again
i = 1, count = 5
nums = [3.5, 3.6, 4.2]
again
i = 1, count = 6
nums = [2.0, 3.2, 3.5, 3.6, 4.2, 4.5]
i = 2, count = 5
nums = [4.5, 4.1, 4.0, 3.9, 3.8]
i = 3, count = 6
nums = [4.3, 3.8]
again
i = 3, count = 5
nums = [3.0, 3.4, 4.6, 3.6, 3.1]

等等

而我得到的是

i = 1, count = 7
nums = [4.2, 4.4, 2.9, 4.4, 3.2, 2.6]
again
nums = [4.2, 4.4, 2.9, 4.4, 3.2, 2.6, 4.0, 1.4, 3.5, 3.6, 3.5, 4.4, 2.9]
i = 2, count = 4

again
nums = [4.5, 4.1, 4.0, 3.9]
i = 3, count = 6
nums = [4.3, 3.8]
again
nums = [4.3, 3.8, 3.6, 2.3, 3.4, 4.6, 3.6, 3.1]
i = 4, count = 5
nums = [1.4, 3.0, 4.0, 4.4, 4.0]
i = 5, count = 7
nums = [4.4, 2.9, 3.5, 4.2, 3.6, 4.4, 4.6]

等等

把它全部放在一个函数中,每当 num 小于或等于 0

时再次调用它
import time
import random
import math

start = 1
stop = 10

def whatever():
    for i in range(start, stop):
        time.sleep(1)
        print("\ni = {}".format(i), end = "")
        count = 3 + random.randint(1,5)
        print(", count = {}".format(count))
        nums = []
        while len(nums) < count:
            for j in range(count):
                time.sleep(0.3)
                num = random.randint(-10,100)

                if num <= 0:
                    time.sleep(2)
                    print("\nagain")
                    whatever()
                else:
                    log = round(math.log(num),1)
                    nums.append(log)

                print("\rnums = {}".format(nums), end = "")

whatever()

如果 num 小于或等于 0

,循环将从这里再次开始
if num <= 0:
    time.sleep(2)
    print("\nagain")
    whatever()

输出:

i = 1, count = 8
nums = [4.2, 2.9, 3.8, 2.1, 4.0, 4.1, 3.8, 4.4]
i = 2, count = 5
nums = [3.4, 3.2, 3.6, 4.5]
again

i = 1, count = 8
nums = [3.5, 4.2, 4.3, 3.9, 3.5, 4.3, 1.1, 3.2]
i = 2, count = 7

again

i = 1, count = 8
nums = [2.4, 3.0, 4.5, 4.1, 4.2, 4.5, 3.6]