当答案 == true 时如何使 void 不是 return

Question

我制作了这个程序，当我输入“是”时，它应该结束我的程序，而不是它在等我说更多的话，然后它随我的 void nottrue() 一起出现；我应该怎么做才能避免这种情况？这是我的代码

#include <iostream>

using namespace std;

void CharacterWorld();
void nottrue();

int main()
{
    CharacterWorld();
    nottrue();
    return 0;
}

void CharacterWorld()
{
    string CharacterName;
    int CharacterAge;
    string yesorno;
    cout << " Hi, welcome to the Vanish World! " << endl;
    cout << " What's your name champion? " << endl;
    cin >> CharacterName;
    cout << " ...And what's your age? " << endl;
    cin >> CharacterAge;
    cout << " ... So your name is " << CharacterName << " and your age is " << CharacterAge << " Is that right?" << endl;
    cin >> yesorno;
    if (yesorno == "yes")
    {
        cout << " Okey! so let's start your journey champion!" << endl;
    }
    else
    {
        cout << " SO what's your name then ??" << endl;
        return nottrue();
    }
}

void nottrue()
{
    string CharacterName;
    int CharacterAge;
    string yesorno;
    cin >> CharacterName;
    cout << " and what's your age?" << endl;
    cin >> CharacterAge;
    cout << " ...Okey, already. Your name is " << CharacterName << " and your age is " << CharacterAge << endl;
}

Answer 1

虽然return nottrue()有效，但它只是一个函数调用，因为调用者和被调用函数都没有返回值。您不会以任何方式改变流量。您必须使用函数返回的结果来控制流程。例如

bool CharacterWorld()
{
    //...
    if (yesorno == "yes")
    {
        cout << " Okey! so let's start your journey champion!" << endl;
        return true;
    }
    else
    {
        cout << " SO what's your name then ??" << endl;
        return false;
    }
}

int main()
{
    if(!CharacterWorld())
        nottrue();
    return 0;
}

还有预定义的exit()函数可以退出程序。

当答案 == true 时如何使 void 不是 return

How to make void not return when answer == true

c++

main

if-statement

return

void