排序格式不正确的日期

Question

我从 excel sheet 获取输入，日期不是可以操作的正确 ISO 格式，即该列如下所示，我正在尝试使用它进行排序使用 javascript 日期和时刻将其转换为正确的日期但是我没有得到正确的输出我可以在这个问题上使用第二个意见。

输入["28/02/23","31/12/21","31/05/21","30/09/23","31/10/22","30/09/21","30/06/23","31/05/22","30/04/21","31/07/21","30/06/21","28/02/22","31/12/22","30/06/22","31/08/21","30/04/22","31/10/20","31/08/22","31/07/22","31/05/23","31/01/23","30/04/23","30/09/22","28/02/21","30/11/20","30/11/21","31/01/21","31/03/23","31/01/22","31/07/23","31/12/20","31/03/21","31/08/23","30/11/22","31/10/21","31/03/22","30/09/20"]

我写的方法

dateCompare = (d1, d2) => {
  let d1Component = d1.toString().split('/')
    , d2Component = d2.toString().split('/')
    , rD1 = new Date(parseInt(20 + d1Component[2]), d1Component[1] - 1, d1Component[0])
    , rD2 = new Date(parseInt(20 + d2Component[2]), d2Component[1] - 1, d2Component[0])
  return moment(rD1).isAfter(moment(rD2))
}

我从上述方法得到的输出是 ["30/09/35", "28/02/23", "31/05/21", "31/12/21", "31/10/22", "30/09/21", "30/09/20", "31/05/22", "30/04/21", "31/07/21", "30/06/21", "28/02/22", "31/12/22", "30/06/22", "31/08/21", "30/04/22", "31/10/20", "31/08/22", "31/07/22", "31/03/22", "31/01/23", "31/10/21", "30/09/22", "28/02/21", "30/11/20", "30/11/21", "31/01/21", "30/11/22", "31/01/22", "31/03/21", "31/12/20", "31/01/37", "31/07/23", "31/03/23", "30/04/23", "31/05/23", "30/06/23", "30/04/37", "31/10/23", "31/08/23", "30/09/23", "30/06/37", "29/02/24", "30/11/23", "31/12/23", "31/01/24", "31/08/37", "31/07/24", "31/03/24", "30/04/24", "31/05/24", "30/06/24", "30/11/37", "31/01/25", "31/08/24", "30/09/24", "31/10/24", "30/11/24", "31/12/24", "31/03/38", "31/08/25", "28/02/25", "31/03/25", "30/04/25"]，我认为它根本没有以任何方式排序。

Answer 1

比较函数应该return负数表示小于，正数表示大于，0表示等于，而不是true/false .此外，由于您已经在使用 moment，因此也可以使用它来解析日期：

function dateCompare(d1, d2) {
    const d1Parsed = moment(d1, "DD/MM/YY");
    const d2Parsed = moment(d2, "DD/MM/YY");
    if (d1Parsed.isBefore(d2Parsed)) {
        return -1;
    } else if (d1Parsed.isSame(d2Parsed)) {
        return 0;
    } else {
        return 1;
    }
}

或者，取它们时间戳的差值（如果 d1Parsed 在 d2Parsed 之前，那么它的时间戳会更小，所以减法结果将为负数，如果它们相等为 0，如果更大则为正，与前面的代码做同样的事情）：

function dateCompare(d1, d2) {
    const d1Parsed = moment(d1, "DD/MM/YY");
    const d2Parsed = moment(d2, "DD/MM/YY");
    return d1Parsed.valueOf() - d2Parsed.valueOf();
}

Answer 2

您可以使用地图并转换日期，而不是对它们进行排序。

const dates = ["28/02/23", "31/12/21", "31/05/21", "30/09/23", "31/10/22", "30/09/21", "30/06/23", "31/05/22", "30/04/21", "31/07/21", "30/06/21", "28/02/22", "31/12/22", "30/06/22", "31/08/21", "30/04/22", "31/10/20", "31/08/22", "31/07/22", "31/05/23", "31/01/23", "30/04/23", "30/09/22", "28/02/21", "30/11/20", "30/11/21", "31/01/21", "31/03/23", "31/01/22", "31/07/23", "31/12/20", "31/03/21", "31/08/23", "30/11/22", "31/10/21", "31/03/22", "30/09/20"];

const convertedDates = dates.map(d => {
  var day = d.split("/")[0];
  var month = d.split("/")[1];
  var year = d.split("/")[2];

  return "20" + year + '-' + ("0" + month).slice(-2) + '-' + ("0" + day).slice(-2);
})
.sort();
;

console.log(convertedDates);

Answer 3

在不使用第三方库的情况下，您可以将自定义日期转换为符合 ISO 8601 的日期字符串并使用 String#localeCompare.

const
    getISO = string => string.replace(/(\d\d)\/(\d\d)\/(\d\d)/, '20--'),
    data = ["28/02/23", "31/12/21", "31/05/21", "30/09/23", "31/10/22", "30/09/21", "30/06/23", "31/05/22", "30/04/21", "31/07/21", "30/06/21", "28/02/22", "31/12/22", "30/06/22", "31/08/21", "30/04/22", "31/10/20", "31/08/22", "31/07/22", "31/05/23", "31/01/23", "30/04/23", "30/09/22", "28/02/21", "30/11/20", "30/11/21", "31/01/21", "31/03/23", "31/01/22", "31/07/23", "31/12/20", "31/03/21", "31/08/23", "30/11/22", "31/10/21", "31/03/22", "30/09/20"];

data.sort((a, b) => getISO(a).localeCompare(getISO(b)));

console.log(data);

排序格式不正确的日期

Sorting dates which are not in right format

javascript

sorting

date

node.js

momentjs