Where Exist 子句的替代 MySQL
Alternative to Where Exist clause MySQL
我有这个 select 语句,在更大的数据集上 运行 需要相当长的时间
select lookup_svcscat_svcscatnew.SVCSCAT_NEW_DESC as svc_type,
enrolid, msclmid, dx1, dx2, dx3,
proc1,msk_cpt_mapping.surg_length_cd as SL_CD,
msk_cpt_mapping.days as day_window,o.svcdate_form, pay,
table_label
from ccaeo190_ky o
left join lookup_svcscat_svcscatnew on o.svcscat = lookup_svcscat_svcscatnew.svcscat
left join msk_cpt_mapping on o.proc1 = msk_cpt_mapping.cpt_code
where EXISTS
(
select 1
from eoc_op_mapping e
where e.msclmid = o.msclmid
and e.enrolid = o.enrolid
and proc1 =27447
)
ORDER BY svcdate_form, msclmid;
我想 return 我的 ccaeo190_ky table 中满足 table eoc_op_mapping 上的 where EXISTS 子句要求的任何行。有什么方法可以使用连接或 select 语句来实现这些结果吗?
我在想:
select lookup_svcscat_svcscatnew.SVCSCAT_NEW_DESC as svc_type,
o.enrolid, o.msclmid, dx1, dx2, dx3,
proc1,msk_cpt_mapping.surg_length_cd as SL_CD,
msk_cpt_mapping.days as day_window,o.svcdate_form, pay,
table_label
from ccaeo190_ky o
left join lookup_svcscat_svcscatnew on o.svcscat = lookup_svcscat_svcscatnew.svcscat
left join msk_cpt_mapping on o.proc1 = msk_cpt_mapping.cpt_code
inner join
(select msclmid, SUM(IF(proc1 = 27447,1,0)) AS cpt
from eoc_op_mapping
group by enrolid
HAVING cpt > 0) e
on e.enrolid = o.enrolid
group by o.enrolid;
但不知道这个方向对不对
通常 EXISTS
比连接执行得更好。
如果您想尝试加入,这相当于您的 WHERE EXISTS
:
.......................................................
inner join (
select distinct msclmid, enrolid
from eoc_op_mapping
where proc1 = 27447
) e on e.msclmid = o.msclmid and e.enrolid = o.enrolid
.......................................................
如果 eoc_op_mapping
中没有重复的 msclmid, enrolid
组合,您可以删除 distinct
。
我有这个 select 语句,在更大的数据集上 运行 需要相当长的时间
select lookup_svcscat_svcscatnew.SVCSCAT_NEW_DESC as svc_type,
enrolid, msclmid, dx1, dx2, dx3,
proc1,msk_cpt_mapping.surg_length_cd as SL_CD,
msk_cpt_mapping.days as day_window,o.svcdate_form, pay,
table_label
from ccaeo190_ky o
left join lookup_svcscat_svcscatnew on o.svcscat = lookup_svcscat_svcscatnew.svcscat
left join msk_cpt_mapping on o.proc1 = msk_cpt_mapping.cpt_code
where EXISTS
(
select 1
from eoc_op_mapping e
where e.msclmid = o.msclmid
and e.enrolid = o.enrolid
and proc1 =27447
)
ORDER BY svcdate_form, msclmid;
我想 return 我的 ccaeo190_ky table 中满足 table eoc_op_mapping 上的 where EXISTS 子句要求的任何行。有什么方法可以使用连接或 select 语句来实现这些结果吗?
我在想:
select lookup_svcscat_svcscatnew.SVCSCAT_NEW_DESC as svc_type,
o.enrolid, o.msclmid, dx1, dx2, dx3,
proc1,msk_cpt_mapping.surg_length_cd as SL_CD,
msk_cpt_mapping.days as day_window,o.svcdate_form, pay,
table_label
from ccaeo190_ky o
left join lookup_svcscat_svcscatnew on o.svcscat = lookup_svcscat_svcscatnew.svcscat
left join msk_cpt_mapping on o.proc1 = msk_cpt_mapping.cpt_code
inner join
(select msclmid, SUM(IF(proc1 = 27447,1,0)) AS cpt
from eoc_op_mapping
group by enrolid
HAVING cpt > 0) e
on e.enrolid = o.enrolid
group by o.enrolid;
但不知道这个方向对不对
通常 EXISTS
比连接执行得更好。
如果您想尝试加入,这相当于您的 WHERE EXISTS
:
.......................................................
inner join (
select distinct msclmid, enrolid
from eoc_op_mapping
where proc1 = 27447
) e on e.msclmid = o.msclmid and e.enrolid = o.enrolid
.......................................................
如果 eoc_op_mapping
中没有重复的 msclmid, enrolid
组合,您可以删除 distinct
。