Django 查询：如何通过帐户所有者创建的博客 post 查询帐户页面？又名 link 从一个到另一个

Question

Django 查询：如何通过帐户所有者创建的博客 post 查询帐户页面？又名 link 从一个到另一个。所以我有一个帐户模型和一个博客 post 模型，作者是外键。我不确定如何查询帐户。谁能建议这通常是如何完成的？因为我尝试执行 user_id=request.user.id 但这会将我带到我自己的帐户视图。谢谢！

html

<a class="dropdown-item" href="{% url 'account:view'  %}">{{blog_post.author}}</a>

views.py

def detail_blog_view(request, slug):
    context = {}
    blog_post = get_object_or_404(BlogPost, slug=slug)
    context['blog_post'] = blog_post
    return render(request, 'HomeFeed/detail_blog.html', context)

urls.py 用于博客


path('<slug>/detail/', detail_blog_view, name= "detail"),

urls.py 帐户：

    path('<user_id>/', account_view, name="view"),

models.py

class Account(AbstractBaseUser):
 email    = models.EmailField(verbose_name="email", max_length=60, unique=True)
 username = models.CharField(max_length=30, unique=True)

class BlogPost(models.Model):
 title  = models.CharField(max_length=50, null=False, blank=False)
 body   = models.TextField(max_length=5000, null=False, blank=False)
 slug   = models.SlugField(blank=True, unique=True)
 author = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE)

Answer 1

你真的不需要查询author，你所做的只是从BlogPost中获取foreign key值像这样的对象：

views.py

def post(request, pk):
    post = BlogPost.objects.get(pk=pk)
    author = post.author
    return render(request, 'post.html', {'post': post,
                                         'author': author})

然后在模板中显示：

post.html

<a href="{% url 'view' author.pk %}">{{ author }}</a>
(or you can use {{ post.author }} here aswell) says:
{{ post.title }} | {{ post.body }}

编辑

在您拥有用户配置文件路径的网址中，您实际上需要指定参数类型，例如：

path('<int:user_id>/', account_view, name="view"), # btw dont call your views 'view', name should describe what the view actually does or shows

Django 查询：如何通过帐户所有者创建的博客 post 查询帐户页面？又名 link 从一个到另一个

Django Querying: How do i query an account page through a blog post that the account owner has created? aka link from one to another

python

django

querying