如何从异步存储中删除选定的项目？

Question

我正在制作一个简单的电影观看列表应用程序。我使用 asyncstorage 来保存选定的电影。我想删除用户在观看列表部分选择的电影。现在我正在尝试这段代码：

    removeItemValue= async (item, index) => {
    let value1 = await AsyncStorage.getItem('movies');
    value1 =JSON.parse(value1);
    console.log("value1"+value)
    //value = item.splice(index,1)
    if (value1 !== null){
        //var index = value.indexOf(x => x.Title === item.Title);
        if (index > -1){
        value1.splice(index, 1);
        await AsyncStorage.removeItem('movies');
        
        AsyncStorage.setItem('movies',JSON.stringify(value)); 
        
    }
    }       
    
}

但这不起作用。你能告诉我哪里错了吗？

还有我的点击部分：

Answer 1

请试试这个

var moviesArray = [{title:'A1'},{title:'A2'},{title:'A3'},{title:'A4'},{title:'A5'},{title:'A6'},{title:'A7'},]

removeSelectedMovie=(name)=>{
return moviesArray.filter(item=>item.title.toLowerCase() !== name.toLowerCase())
}

//removeSelectedMovie(MovieName here and its will return a //new array excluded selected movie name)
console.log(removeSelectedMovie('a1'))
console.log(removeSelectedMovie('a3'))
console.log(removeSelectedMovie('a4'))
console.log(removeSelectedMovie('a7'))

Answer 2

removeItemValue = async(index) => { // don't need item here
  // avoid mutations, create new variables
  const rawValue = await AsyncStorage.getItem('movies');
  try {
    const jsonValue = JSON.parse(rawValue) || []; // avoid undefined or null
    const finalValue = [...jsonValue.slice(0, index), ...jsonValue.slice(index + 1)];
    await AsyncStorage.setItem('movies', JSON.stringify(finalValue)); // add await here
  } catch (e) {
    console.log('Parsing failed', e)
  }
}

并使用 () => this.removeItemValue(index)

删除

如何从异步存储中删除选定的项目？

How can i remove a selected item from asyncstorage?

javascript

react-native

asyncstorage