如何为 pygame 上的输入文本框模块设置条件？
How can I set conditions for an inputting textbox module on pygame?
我是 python 的初学者，目前正在使用 pygame。我正在制作一款需要用户输入的游戏。我有一个名为“Typing_Questions”的算法，它对用户犯错时的得分和寿命有条件。该算法 运行 正确。它 运行 是 pygame 底部的脚本，因此它不会加载单独的屏幕。
Typing_Questions:
Score = 0
Lives = 3
Question_4 = "Code print"
Answer = "print"
print(T_Question_4)
user_input = input("Enter: ")
if user_input == Answer:
Lives = Lives
Score = Score + 1
print(Lives)
print(Score)
print("Well Done!")
while user_input != Answer:
user_input = input()
if user_input == Answer:
Lives = Lives
Score = Score + 1
print(Lives)
print(Score)
print("Well Done!")
else:
Lives = Lives - 1
Score = Score - 1
print(Lives)
if Score == -1:
Score = 0
print(Score)
if Lives == 0:
print("Game Over")
quit()
else:
print("Try again.")
print(T_Question_4)
我也有一个输入文本框的算法。这让我可以输入任何内容并加载一个单独的屏幕。这也能正常工作。
文本框：
import pygame as pg
def main():
screen = pg.display.set_mode((1275, 775))
font = pg.font.Font(None, 32)
clock = pg.time.Clock()
input_box = pg.Rect(400, 300, 142, 32)
color_inactive = pg.Color('lighskyblue3')
color_active = pg.Color('dodgerblue2')
color = color_inactive
active = False
text = ''
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
if event.type == pg.MOUSEBUTTONDOWN:
if input_box.collidepoint(event.pos):
active = not active
else:
active = False
color = color_active if active else color_inactive
if event.type == pg.KEYDOWN:
if active:
if event.key == pg.K_RETURN:
print(text)
text = ''
elif event.key == pg.K_BACKSPACE:
text = text[:-1]
else:
text += event.unicode
screen.fill(250, 250, 250)
txt_surface = font.render(text, True, color)
width = max(200, txt_surface.get_width()+10)
input_box.w = width
screen.blit(txt_surface, (input_box.x + 5, input_box.y + 5))
pg.draw.rect(screen, color, input_box, 2)
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
pg.init()
main()
pg.quit()
我的目标是将这两个模块合并在一起。我尝试将另一个导入到一个模块中，但只有 Typing_Questions 会 运行 并且屏幕不会为文本框模块加载，反之亦然。
我希望显示文本框屏幕，以便用户可以从那里输入他们的答案。当他们在框中回答时，我希望程序遵循 Typing_Questions 算法的脚本（因此它只会接受答案，否则它会减少生命或在必要时结束程序）。
有办法吗？谢谢。
使用 答案中的示例作为您申请的基础。该示例包含实现文本输入框的完整 class。
您必须实施应用程序循环。有关实现应用程序循环的更多信息，请参阅 .
的答案
典型的 PyGame 应用程序循环必须：
- 通过
pygame.event.pump() or pygame.event.get() 处理事件。
- 根据输入事件和时间（分别为帧）更新对象的游戏状态和位置
- 清除整个显示或绘制背景
- 绘制整个场景（
blit 所有对象）
- 通过
pygame.display.update() or pygame.display.flip() 更新显示
列出问题和问题的答案。为 score、lives 和 current_question 指定变量。例如：
questions = ["question 1", "question 2", "question 3"]
answer = ["answer 1", "answer 2", "answer 3"]
current_question = 0
lives = 3
score = 0
使用应用程序循环从文本输入字段获取输入。评估结果并相应地更改 score、lives 和 current_question 的变量：
while run:
# [...]`
if lives > 0 and current_question < len(questions):
group.update(event_list)
if not text_input_box.active:
if text_input_box.text == answer[current_question]:
score += 1
current_question += 1
else:
lives -= 1
text_input_box.reset()
参见 Python display text with font & color? 并生成文本输出。对于输入：
game_over_surf = font100.render("Game Over", True, (255, 255, 255))
window.blit(game_over_surf, game_over_surf.get_rect(center = window.get_rect().center))
完整示例：
import pygame
class TextInputBox(pygame.sprite.Sprite):
def __init__(self, x, y, w, font):
super().__init__()
self.color = (255, 255, 255)
self.backcolor = None
self.pos = (x, y)
self.width = w
self.font = font
self.active = True
self.text = ""
self.render_text()
def render_text(self):
t_surf = self.font.render(self.text, True, self.color, self.backcolor)
self.image = pygame.Surface((max(self.width, t_surf.get_width()+10), t_surf.get_height()+10), pygame.SRCALPHA)
if self.backcolor:
self.image.fill(self.backcolor)
self.image.blit(t_surf, (5, 5))
pygame.draw.rect(self.image, self.color, self.image.get_rect().inflate(-2, -2), 2)
self.rect = self.image.get_rect(topleft = self.pos)
def reset(self):
self.text = ""
self.active = True
self.render_text()
def update(self, event_list):
for event in event_list:
if event.type == pygame.KEYDOWN and self.active:
if event.key == pygame.K_RETURN:
self.active = False
elif event.key == pygame.K_BACKSPACE:
self.text = self.text[:-1]
else:
self.text += event.unicode
self.render_text()
questions = ["question 1", "question 2", "question 3"]
answer = ["answer 1", "answer 2", "answer 3"]
current_question = 0
lives = 3
score = 0
pygame.init()
window = pygame.display.set_mode((500, 500))
clock = pygame.time.Clock()
font100 = pygame.font.SysFont(None, 100)
font50 = pygame.font.SysFont(None, 50)
text_input_box = TextInputBox(20, 170, 460, font100)
group = pygame.sprite.Group(text_input_box)
run = True
while run:
clock.tick(60)
event_list = pygame.event.get()
for event in event_list:
if event.type == pygame.QUIT:
run = False
if lives > 0 and current_question < len(questions):
group.update(event_list)
if not text_input_box.active:
if text_input_box.text == answer[current_question]:
score += 1
current_question += 1
else:
lives -= 1
text_input_box.reset()
window.fill(0)
if lives == 0:
game_over_surf = font100.render("Game Over", True, (255, 255, 255))
window.blit(game_over_surf, game_over_surf.get_rect(center = window.get_rect().center))
elif current_question < len(questions):
question_surf = font100.render(questions[current_question], True, (255, 255, 255))
window.blit(question_surf, (20, 50))
group.draw(window)
else:
well_done_surf = font100.render("Well Done!", True, (255, 255, 255))
window.blit(well_done_surf, well_done_surf.get_rect(center = window.get_rect().center))
score_surf = font50.render("score: " + str(score), True, (255, 255, 255))
window.blit(score_surf, (20, 400))
lives_surf = font50.render("lives: " + str(lives), True, (255, 255, 255))
window.blit(lives_surf, (300, 400))
pygame.display.flip()
pygame.quit()
exit()
我是 python 的初学者，目前正在使用 pygame。我正在制作一款需要用户输入的游戏。我有一个名为“Typing_Questions”的算法，它对用户犯错时的得分和寿命有条件。该算法 运行 正确。它 运行 是 pygame 底部的脚本，因此它不会加载单独的屏幕。
Typing_Questions:
Score = 0
Lives = 3
Question_4 = "Code print"
Answer = "print"
print(T_Question_4)
user_input = input("Enter: ")
if user_input == Answer:
Lives = Lives
Score = Score + 1
print(Lives)
print(Score)
print("Well Done!")
while user_input != Answer:
user_input = input()
if user_input == Answer:
Lives = Lives
Score = Score + 1
print(Lives)
print(Score)
print("Well Done!")
else:
Lives = Lives - 1
Score = Score - 1
print(Lives)
if Score == -1:
Score = 0
print(Score)
if Lives == 0:
print("Game Over")
quit()
else:
print("Try again.")
print(T_Question_4)
我也有一个输入文本框的算法。这让我可以输入任何内容并加载一个单独的屏幕。这也能正常工作。
文本框：
import pygame as pg
def main():
screen = pg.display.set_mode((1275, 775))
font = pg.font.Font(None, 32)
clock = pg.time.Clock()
input_box = pg.Rect(400, 300, 142, 32)
color_inactive = pg.Color('lighskyblue3')
color_active = pg.Color('dodgerblue2')
color = color_inactive
active = False
text = ''
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
if event.type == pg.MOUSEBUTTONDOWN:
if input_box.collidepoint(event.pos):
active = not active
else:
active = False
color = color_active if active else color_inactive
if event.type == pg.KEYDOWN:
if active:
if event.key == pg.K_RETURN:
print(text)
text = ''
elif event.key == pg.K_BACKSPACE:
text = text[:-1]
else:
text += event.unicode
screen.fill(250, 250, 250)
txt_surface = font.render(text, True, color)
width = max(200, txt_surface.get_width()+10)
input_box.w = width
screen.blit(txt_surface, (input_box.x + 5, input_box.y + 5))
pg.draw.rect(screen, color, input_box, 2)
pg.display.flip()
clock.tick(30)
if __name__ == '__main__':
pg.init()
main()
pg.quit()
我的目标是将这两个模块合并在一起。我尝试将另一个导入到一个模块中，但只有 Typing_Questions 会 运行 并且屏幕不会为文本框模块加载，反之亦然。
我希望显示文本框屏幕，以便用户可以从那里输入他们的答案。当他们在框中回答时，我希望程序遵循 Typing_Questions 算法的脚本（因此它只会接受答案，否则它会减少生命或在必要时结束程序）。
有办法吗？谢谢。
使用
您必须实施应用程序循环。有关实现应用程序循环的更多信息，请参阅
典型的 PyGame 应用程序循环必须：
- 通过
pygame.event.pump()orpygame.event.get()处理事件。 - 根据输入事件和时间（分别为帧）更新对象的游戏状态和位置
- 清除整个显示或绘制背景
- 绘制整个场景（
blit所有对象） - 通过
pygame.display.update()orpygame.display.flip() 更新显示
列出问题和问题的答案。为 score、lives 和 current_question 指定变量。例如：
questions = ["question 1", "question 2", "question 3"]
answer = ["answer 1", "answer 2", "answer 3"]
current_question = 0
lives = 3
score = 0
使用应用程序循环从文本输入字段获取输入。评估结果并相应地更改 score、lives 和 current_question 的变量：
while run:
# [...]`
if lives > 0 and current_question < len(questions):
group.update(event_list)
if not text_input_box.active:
if text_input_box.text == answer[current_question]:
score += 1
current_question += 1
else:
lives -= 1
text_input_box.reset()
参见 Python display text with font & color? 并生成文本输出。对于输入：
game_over_surf = font100.render("Game Over", True, (255, 255, 255))
window.blit(game_over_surf, game_over_surf.get_rect(center = window.get_rect().center))
完整示例：
import pygame
class TextInputBox(pygame.sprite.Sprite):
def __init__(self, x, y, w, font):
super().__init__()
self.color = (255, 255, 255)
self.backcolor = None
self.pos = (x, y)
self.width = w
self.font = font
self.active = True
self.text = ""
self.render_text()
def render_text(self):
t_surf = self.font.render(self.text, True, self.color, self.backcolor)
self.image = pygame.Surface((max(self.width, t_surf.get_width()+10), t_surf.get_height()+10), pygame.SRCALPHA)
if self.backcolor:
self.image.fill(self.backcolor)
self.image.blit(t_surf, (5, 5))
pygame.draw.rect(self.image, self.color, self.image.get_rect().inflate(-2, -2), 2)
self.rect = self.image.get_rect(topleft = self.pos)
def reset(self):
self.text = ""
self.active = True
self.render_text()
def update(self, event_list):
for event in event_list:
if event.type == pygame.KEYDOWN and self.active:
if event.key == pygame.K_RETURN:
self.active = False
elif event.key == pygame.K_BACKSPACE:
self.text = self.text[:-1]
else:
self.text += event.unicode
self.render_text()
questions = ["question 1", "question 2", "question 3"]
answer = ["answer 1", "answer 2", "answer 3"]
current_question = 0
lives = 3
score = 0
pygame.init()
window = pygame.display.set_mode((500, 500))
clock = pygame.time.Clock()
font100 = pygame.font.SysFont(None, 100)
font50 = pygame.font.SysFont(None, 50)
text_input_box = TextInputBox(20, 170, 460, font100)
group = pygame.sprite.Group(text_input_box)
run = True
while run:
clock.tick(60)
event_list = pygame.event.get()
for event in event_list:
if event.type == pygame.QUIT:
run = False
if lives > 0 and current_question < len(questions):
group.update(event_list)
if not text_input_box.active:
if text_input_box.text == answer[current_question]:
score += 1
current_question += 1
else:
lives -= 1
text_input_box.reset()
window.fill(0)
if lives == 0:
game_over_surf = font100.render("Game Over", True, (255, 255, 255))
window.blit(game_over_surf, game_over_surf.get_rect(center = window.get_rect().center))
elif current_question < len(questions):
question_surf = font100.render(questions[current_question], True, (255, 255, 255))
window.blit(question_surf, (20, 50))
group.draw(window)
else:
well_done_surf = font100.render("Well Done!", True, (255, 255, 255))
window.blit(well_done_surf, well_done_surf.get_rect(center = window.get_rect().center))
score_surf = font50.render("score: " + str(score), True, (255, 255, 255))
window.blit(score_surf, (20, 400))
lives_surf = font50.render("lives: " + str(lives), True, (255, 255, 255))
window.blit(lives_surf, (300, 400))
pygame.display.flip()
pygame.quit()
exit()