按函数结果弹性搜索顺序(sqrt)
elastic search order by function result (sqrt)
我在elastic中保存了以下数据
{
"data" : {
"c1" : -0.343404934,
"c2" : -0.1234212345,
"c3" : 0.003404934
}
}
我需要用平方根对每个字段的功率求和进行排序。
在 sql 我会这样写:
SELECT c1,c2,c3 from table
ORDER BY sqrt(
power(c1 - external_param_c1, 2) + power(c2 - external_param_c2, 2) + power(c2 - external_param_c3, 2)
)
如何将其转换为 elastic?
谢谢
看来你需要 scripted sort utilizing the Math
painless library:
{
"sort": [
{
"_script": {
"type": "number",
"order": "desc",
"script": {
"source": "Math.sqrt(Math.pow(doc['data.c1'].value - params.external_param_c1, 2) + Math.pow(doc['data.c2'].value - params.external_param_c2, 2) + Math.pow(doc['data.c3'].value - params.external_param_c3, 2))",
"params": {
"external_param_c1": 1,
"external_param_c2": 2,
"external_param_c3": 3
}
}
}
}
]
}
我在elastic中保存了以下数据
{
"data" : {
"c1" : -0.343404934,
"c2" : -0.1234212345,
"c3" : 0.003404934
}
}
我需要用平方根对每个字段的功率求和进行排序。
在 sql 我会这样写:
SELECT c1,c2,c3 from table
ORDER BY sqrt(
power(c1 - external_param_c1, 2) + power(c2 - external_param_c2, 2) + power(c2 - external_param_c3, 2)
)
如何将其转换为 elastic?
谢谢
看来你需要 scripted sort utilizing the Math
painless library:
{
"sort": [
{
"_script": {
"type": "number",
"order": "desc",
"script": {
"source": "Math.sqrt(Math.pow(doc['data.c1'].value - params.external_param_c1, 2) + Math.pow(doc['data.c2'].value - params.external_param_c2, 2) + Math.pow(doc['data.c3'].value - params.external_param_c3, 2))",
"params": {
"external_param_c1": 1,
"external_param_c2": 2,
"external_param_c3": 3
}
}
}
}
]
}