如何在 Python 中使用插入排序根据学生的分数对学生列表进行排序

Question

我正在尝试使用插入排序对学生列表进行排序，并根据他们的分数对每个学生进行排名。学生数据包括姓名、学号、地址、分数。

在这里，我将学生的分数存储在一个列表中 - Marklist，将学生的其他数据存储在第二个列表中 - stdData。

我使用插入排序对学生成绩单进行了排序。但现在我有 2 个单独的列表。如何合并并打印每个学生的排序列表及其分数？

import csv
stdData = []  # store RollNum,student name last name,address
Marklist = []  # store the final mark of each student
#generallist=[]
with open("studentlist.csv", "r") as f1:
    recordReader = csv.DictReader(f1)
    for row in recordReader:
        #generallist.append(row)
        row['Mark']=int(row['Mark'])
        Marklist.append(row['Mark'])
        stdData.append(row['RollNo'])
        stdData.append(row['Name'])
        stdData.append(row['LastName'])
        stdData.append(row['Address'])
print(Marklist)
print(stdData)
for i in range(1, len(Marklist)):
    key = Marklist[i]
    j = i - 1
    while j >= 0 and key < Marklist[j]:
        Marklist[j + 1] = Marklist[j]
        j -= 1
    Marklist[j + 1] = key

   print("Sorted List: ",Marklist)

谢谢。

Answer 1

您非常接近正确的解决方案。答案就在

将学生详细信息存储为列表列表。例如：[ [student1 details], [student2 details], [student3 details] ]
使用 MarkList 的索引排序 stdData。

下面是为解决上述问题而修改的代码：

import csv
stdData = []  # store RollNum,student name last name,address
Marklist = []  # store the final mark of each student
generallist=[]
with open("studentlist.csv", "r") as f1:
    recordReader = csv.DictReader(f1)
    for row in recordReader:
        #generallist.append(row)
        row['Mark']=int(row['Mark'])
        Marklist.append(row['Mark'])
        tmp_data = []
        tmp_data.append(row['RollNo'])
        tmp_data.append(row['Name'])
        tmp_data.append(row['LastName'])
        tmp_data.append(row['Address'])
        stdData.append(tmp_data) # Storing student details as list of lists
print(Marklist)
print(stdData)
for i in range(1, len(Marklist)):
    key = Marklist[i]
    data = stdData[i] # Sort the elements in stdData using indices of MarkList
    j = i - 1
    while j >= 0 and key < Marklist[j]:
        Marklist[j + 1] = Marklist[j]
        stdData[j+1] = stdData[j]
        j -= 1
    Marklist[j + 1] = key
    stdData[j+1] = data
print("Sorted List: ",Marklist)
for student_data in stdData:
    print(student_data)

尽管上述解决方案给出了正确答案，但它使用了两个列表。

我们可以使用键对列表进行排序（不需要是实际的列表元素）。下面的代码实现了它，是一个更好的解决方案。

import csv
stdData = []  # store RollNum,student name last name,address

with open("studentlist.csv", "r") as f1:
    recordReader = csv.DictReader(f1)
    for row in recordReader:
        tmp_data = []
        tmp_data.append(row['RollNo'])
        tmp_data.append(row['Name'])
        tmp_data.append(int(row['Mark']))
        tmp_data.append(row['LastName'])
        tmp_data.append(row['Address'])
        stdData.append(tmp_data) # Storing student details as list of lists

print(stdData)
for i in range(1, len(stdData)):
    key = stdData[i][2] # here the key is the mark
    data = stdData[i] # we will copy the data to correct index
    j = i - 1
    while j >= 0 and key < stdData[j][2]:
        stdData[j+1] = stdData[j]
        j -= 1
    stdData[j+1] = data

print("Sorted List:")
for rollno, name, mark, lastname, address in stdData:
    print(rollno, name, mark, lastname, address)

编码愉快。

如何在 Python 中使用插入排序根据学生的分数对学生列表进行排序

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