Mule 4 - 如何将具有相同 id 字段的嵌套数组中的数组合并为一个
Mule 4 - How to combine arrays inside a nested array with the same id field into one
假设我有以下带有嵌套数组的有效负载,我如何将嵌套数组中的数组组合为相同的 externalId 以及某些字段上的一些逻辑,例如
shipQty - 此字段将对 fillingOrder
下具有相同 externalId 的记录进行求和或相加
serialNumbers - 如果externalId相同,serialNumbers下的所有记录将一起显示
请参阅下面的输入和预期输出
Json 有效载荷输入
{
"Identifier": "9i098p-898j-67586k",
"transactionDate": "2019-09-08T10:01:00-04:00",
"order": [
{
"orderNumber": "123456789",
"CourierOrderId": "1300-88-2525",
"fillingOrder": [
{
"numberOfBoxes": 0,
"tracking": [
{
"carrier": "Orange",
"trackNum": "3333444",
"trackUrl": "https://www.orange.com/track/status",
"shipDate": "2019-09-08T10:01:00-04:00",
"SerialNumber": "00000123"
}
],
"row": [
{
"externalId": "1",
"unitNo": "OP04-123456-789",
"shipQty": 2,
"serialNumbers": [
{
"serialNumber": "USD333555",
"quantity": 1
},
{
"serialNumber": "USD235678",
"quantity": 1
}
]
}
]
},
{
"tracking": [
{
"carrier": "Apple",
"trackNum": "555666",
"trackUrl": "https://www.apple.com/track/status",
"shipDate": "2019-09-08T10:01:00-04:00",
"SerialNumber": "00000645"
}
],
"row": [
{
"externalId": "1",
"unitNo": "OP04-123456-789",
"shipQty": 3,
"serialNumbers": [
{
"serialNumber": "USD123456",
"quantity": 1
},
{
"serialNumber": "USD98765",
"quantity": 1
},
{
"serialNumber": "USD45689",
"quantity": 1
}
]
}
]
},
{
"tracking": [
{
"carrier": "banana",
"trackNum": "587390",
"trackUrl": "https://www.banana.com/track/status",
"shipDate": "2019-09-08T10:01:00-04:00",
"SerialNumber": "00000365"
}
],
"row": [
{
"externalId": "2",
"unitNo": "OP05-123456-111",
"shipQty": 2,
"serialNumbers": [
{
"serialNumber": "USD00045",
"quantity": 1
},
{
"serialNumber": "USD00046",
"quantity": 1
}
]
}
]
}
]
}
]
}
预期Json输出
{
"row": [
{
"externalId": "1",
"unitNo": "OP04-123456-789",
"shipQty": 5, //the shipQty should be add up when the externalId is same
"serialNumbers": [ //the serialNumbers should display all the data inside the serialNumbers when the externalId is same
{
"serialNumber": "USD333555",
"quantity": 1
},
{
"serialNumber": "USD235678",
"quantity": 1
},
{
"serialNumber": "USD123456",
"quantity": 1
},
{
"serialNumber": "USD98765",
"quantity": 1
},
{
"serialNumber": "USD45689",
"quantity": 1
}
]
},
{
"externalId": "2",
"unitNo": "OP05-123456-111",
"shipQty": 2,
"serialNumbers": [
{
"serialNumber": "USD00045",
"quantity": 1
},
{
"serialNumber": "USD00046",
"quantity": 1
}
}
]
}
试试这个:
%dw 2.0
output application/json
---
row:[ if (payload..order..row..externalId[0] == payload..order..row..externalId[1]) {
externalId : payload..order..row..externalId[0],
unitNo: payload..order..row..unitNo[0],
shipQty: payload..order..row..shipQty[0] + payload..order..row..shipQty[1],
serialNumbers: flatten (payload..order..row..serialNumbers)
}
else null]
看起来您只需要有效负载的 fillingOrder 字段中的“行”数据。因此,简化问题的第一件事是将所有行作为一个数组获取。一旦你有了它们,你只需要通过外部 ID 对其进行分组,问题就会开始变得更小。
%dw 2.0
output application/json
//First get all rows since it looks like you only need them.
//If you find this confusing try to use flatten with some simpler payloads.
var allRows = flatten(flatten(payload.order.fillingOrder).row)
//Group them according to external id.
var groupedExtId = allRows groupBy $.externalId
---
{
row: groupedExtId pluck ((value, extId, index) -> do {
var sumShipQuant = sum(value.shipQty default [])
---
{
externalId: (extId), //the key after grouping is external id
unitNo: value.unitNo[0], //assuming it is same across diff external id
shipQty: sumShipQuant,
serialNumbers: flatten(value.serialNumbers) //Flatten because value is an array and it has multiple serielNumbers array
}
})
}
这应该有所帮助。我从 Harshank Bansal post
那里得到了一些灵感
%dw 2.0
output application/json
var groupFlat = flatten(flatten (payload.order.fillingOrder).row) groupBy ($.externalId)
---
row: [groupFlat mapObject ((value, key, index) -> {
externalId: value.externalId[0],
unitNO: value.unitNo[0],
shipQty: sum(value.shipQty),
serialNumbers: flatten(value.serialNumbers)
})]
假设我有以下带有嵌套数组的有效负载,我如何将嵌套数组中的数组组合为相同的 externalId 以及某些字段上的一些逻辑,例如
shipQty - 此字段将对 fillingOrder
下具有相同 externalId 的记录进行求和或相加serialNumbers - 如果externalId相同,serialNumbers下的所有记录将一起显示
请参阅下面的输入和预期输出
Json 有效载荷输入
{
"Identifier": "9i098p-898j-67586k",
"transactionDate": "2019-09-08T10:01:00-04:00",
"order": [
{
"orderNumber": "123456789",
"CourierOrderId": "1300-88-2525",
"fillingOrder": [
{
"numberOfBoxes": 0,
"tracking": [
{
"carrier": "Orange",
"trackNum": "3333444",
"trackUrl": "https://www.orange.com/track/status",
"shipDate": "2019-09-08T10:01:00-04:00",
"SerialNumber": "00000123"
}
],
"row": [
{
"externalId": "1",
"unitNo": "OP04-123456-789",
"shipQty": 2,
"serialNumbers": [
{
"serialNumber": "USD333555",
"quantity": 1
},
{
"serialNumber": "USD235678",
"quantity": 1
}
]
}
]
},
{
"tracking": [
{
"carrier": "Apple",
"trackNum": "555666",
"trackUrl": "https://www.apple.com/track/status",
"shipDate": "2019-09-08T10:01:00-04:00",
"SerialNumber": "00000645"
}
],
"row": [
{
"externalId": "1",
"unitNo": "OP04-123456-789",
"shipQty": 3,
"serialNumbers": [
{
"serialNumber": "USD123456",
"quantity": 1
},
{
"serialNumber": "USD98765",
"quantity": 1
},
{
"serialNumber": "USD45689",
"quantity": 1
}
]
}
]
},
{
"tracking": [
{
"carrier": "banana",
"trackNum": "587390",
"trackUrl": "https://www.banana.com/track/status",
"shipDate": "2019-09-08T10:01:00-04:00",
"SerialNumber": "00000365"
}
],
"row": [
{
"externalId": "2",
"unitNo": "OP05-123456-111",
"shipQty": 2,
"serialNumbers": [
{
"serialNumber": "USD00045",
"quantity": 1
},
{
"serialNumber": "USD00046",
"quantity": 1
}
]
}
]
}
]
}
]
}
预期Json输出
{
"row": [
{
"externalId": "1",
"unitNo": "OP04-123456-789",
"shipQty": 5, //the shipQty should be add up when the externalId is same
"serialNumbers": [ //the serialNumbers should display all the data inside the serialNumbers when the externalId is same
{
"serialNumber": "USD333555",
"quantity": 1
},
{
"serialNumber": "USD235678",
"quantity": 1
},
{
"serialNumber": "USD123456",
"quantity": 1
},
{
"serialNumber": "USD98765",
"quantity": 1
},
{
"serialNumber": "USD45689",
"quantity": 1
}
]
},
{
"externalId": "2",
"unitNo": "OP05-123456-111",
"shipQty": 2,
"serialNumbers": [
{
"serialNumber": "USD00045",
"quantity": 1
},
{
"serialNumber": "USD00046",
"quantity": 1
}
}
]
}
试试这个:
%dw 2.0
output application/json
---
row:[ if (payload..order..row..externalId[0] == payload..order..row..externalId[1]) {
externalId : payload..order..row..externalId[0],
unitNo: payload..order..row..unitNo[0],
shipQty: payload..order..row..shipQty[0] + payload..order..row..shipQty[1],
serialNumbers: flatten (payload..order..row..serialNumbers)
}
else null]
看起来您只需要有效负载的 fillingOrder 字段中的“行”数据。因此,简化问题的第一件事是将所有行作为一个数组获取。一旦你有了它们,你只需要通过外部 ID 对其进行分组,问题就会开始变得更小。
%dw 2.0
output application/json
//First get all rows since it looks like you only need them.
//If you find this confusing try to use flatten with some simpler payloads.
var allRows = flatten(flatten(payload.order.fillingOrder).row)
//Group them according to external id.
var groupedExtId = allRows groupBy $.externalId
---
{
row: groupedExtId pluck ((value, extId, index) -> do {
var sumShipQuant = sum(value.shipQty default [])
---
{
externalId: (extId), //the key after grouping is external id
unitNo: value.unitNo[0], //assuming it is same across diff external id
shipQty: sumShipQuant,
serialNumbers: flatten(value.serialNumbers) //Flatten because value is an array and it has multiple serielNumbers array
}
})
}
这应该有所帮助。我从 Harshank Bansal post
那里得到了一些灵感%dw 2.0
output application/json
var groupFlat = flatten(flatten (payload.order.fillingOrder).row) groupBy ($.externalId)
---
row: [groupFlat mapObject ((value, key, index) -> {
externalId: value.externalId[0],
unitNO: value.unitNo[0],
shipQty: sum(value.shipQty),
serialNumbers: flatten(value.serialNumbers)
})]