c程序打印look and say序列

Question

这是我的代码实际输出和要求的输出略有不同。在实际输出中，每个数字都在新行打印。但我希望输出以 space.

分隔的单行打印

需要输出

示例输入：

1 8

示例输出：

1 11 21 1211 111221 312211 13112221 1113213211

我的代码在这里

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char *a = malloc(2), *b = 0, *x, c;
    int cnt, len = 1,i=1,lim,s;
  scanf("%d",&s);
 scanf("%d",&lim);
    for (sprintf(a, "%d",s); (b = realloc(b, len * 2 + 1)); a = b, b = x)
    {
        puts(x = a);
        for (len = 0, cnt = 1; (c = *a); )
        {
            if (c == *++a)
                cnt++;
            else if (c) 
            {
                len += sprintf(b + len, "%d%c", cnt, c);
                cnt = 1;

            }

        }
      if(i==lim)
        break;
      i++;
    }

    return 0;
}

我的输出

输入 > 1

8

输出>1

11

21

1211

111221

312211

13112221

1113213211

Answer 1

使用

 printf("%s ",a);

而不是

 puts(x = a);

Answer 2

puts automatically appends a newline. If that's not what you want, you can fputs your string to stdout or use printf.

 fputs(x=a,stdout);

或

 printf("%s ",a);

c程序打印look and say序列

c program to print look and say sequence

c

printing

sequence