在 PHP Goutte 中刮取 <script> 标签

Question

我正在使用 PHP Goutte 抓取网站，但我需要一些仅在脚本标记中以下列方式指示的信息：

<script>
player.qualityselector({
        sources: [
          { format: 'auto', src: "xxx.example.com", type: 'video/mp4'},
                        { format: '1080p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '720p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '480p WEB-DL', src: "xxx.example.com4", type: 'video/mp4'},
                          { format: '360p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '240p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
      ],
      });
</script>

我需要每一个的src，可以吗？

Answer 1

您可以使用正则表达式。

例子

$page_content = <<<EOF
<script>
player.qualityselector({
        sources: [
          { format: 'auto', src: "xxx.example.com", type: 'video/mp4'},
                        { format: '1080p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '720p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '480p WEB-DL', src: "xxx.example.com4", type: 'video/mp4'},
                          { format: '360p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '240p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
      ],
      });
</script>
EOF;

preg_match_all('/src:\s"(.*)"/', $page_content, $match);
$result = $match[1];
print_r($result);

输出

Array
(
    [0] => xxx.example.com
    [1] => xxx.example.com
    [2] => xxx.example.com
    [3] => xxx.example.com4
    [4] => xxx.example.com
    [5] => xxx.example.com
)

在 PHP Goutte 中刮取 <script> 标签

Scrape <script> tag in PHP Goutte

javascript

php

web-scraping

goutte