为什么我的 tic tac toe C++ clear board 不起作用

Question

我想如果使用循环功能后，棋盘会很干净，不保存之前的游戏数据。

我试过YouTube上的各种方法，但我还是不想丢失之前的游戏数据。希望有人告诉我如何删除以前的数据。

我尝试了各种方法，搜索了 YouTube、网络和其他网站，但仍然没有用。

这是我的代码：

#include<iostream>
using namespace std;
char data1[3][3];
char pp='X';

void draw()//muncul data1
{
    cout<<endl;
    for(int i=0; i<3; i++)
    {
    cout<<" ----- ----- -----\n";
    cout<<"|     |     |     |\n";
    cout<<"|  "<<data1[i][0]<<"  |  "<<data1[i][1]<<"  |  "<<data1[i][2]<<"  |"<<endl;
    cout<<"|     |     |     |\n";
    }
    cout<<" ----- ----- -----\n";
    cout<<endl;
    cout<<" --- --- ---\n";
    cout<<"| 1 | 2 | 3 |"<<"  Silahkan"<<endl;
    cout<<" --- --- ---\n";
    cout<<"| 4 | 5 | 6 |"<<"    Pilih"<<endl;
    cout<<" --- --- ---\n";
    cout<<"| 7 | 8 | 9 |"<<"  Koordinat"<<endl;
    cout<<" --- --- ---"<<endl;
    cout<<endl;


}
void clear()//hapus data1
{
    for(int i=0; i<3; i++)
    {
        (data1[0][i] == ' ') && (data1[0][i] == data1[1][i]) && (data1[1][i] == data1[2][i]);
    }
}
void input()
{
    int a;
    cout<<"Angka yang anda ingin kan : ";
    cin>>a;
    
    if(a==1)
    {
        data1[0][0] = pp;
    }
    else if(a==2)
    {
        data1[0][1] = pp;
    }
    else if(a==3)
    {
        data1[0][2] = pp;
    }
    else if(a==4)
    {
        data1[1][0] = pp;
    }
    else if(a==5)
    {
        data1[1][1] = pp;
    }
    else if(a==6)
    {
        data1[1][2] = pp;
    }
    else if(a==7)
    {
        data1[2][0] = pp;
    }
    else if(a==8)
    {
        data1[2][1] = pp;
    }
    else if(a==9)
    {
        data1[2][2] = pp;
    }
}
void pla()
{
    if(pp=='X')
        pp = 'O';
    else
        pp = 'X';
    
}
char win()
{
    //player 1
    //horizontal
    if (data1[0][0]=='X' && data1[0][1]=='X' && data1[0][2]=='X')
        return 'X';
    if (data1[1][0]=='X' && data1[1][1]=='X' && data1[1][2]=='X')
        return 'X';
    if (data1[2][0]=='X' && data1[2][1]=='X' && data1[2][2]=='X')
        return 'X';
    //vertikal
    if (data1[0][0]=='X' && data1[1][0]=='X' && data1[2][0]=='X')
        return 'X';
    if (data1[0][1]=='X' && data1[1][1]=='X' && data1[2][1]=='X')
        return 'X';
    if (data1[0][2]=='X' && data1[1][2]=='X' && data1[2][2]=='X')
        return 'X';
    //diagonal
    if (data1[0][0]=='X' && data1[1][1]=='X' && data1[2][2]=='X')
        return 'X';
    if (data1[2][0]=='X' && data1[1][1]=='X' && data1[0][2]=='X')
        return 'X';
    //player 2
    //horizontal
    if (data1[0][0]=='O' && data1[0][1]=='O' && data1[0][2]=='O')
        return 'O';
    if (data1[1][0]=='O' && data1[1][1]=='O' && data1[1][2]=='O')
        return 'O';
    if (data1[2][0]=='O' && data1[2][1]=='O' && data1[2][2]=='O')
        return 'O';
    //vertikal
    if (data1[0][0]=='O' && data1[1][0]=='O' && data1[2][0]=='O')
        return 'O';
    if (data1[0][1]=='O' && data1[1][1]=='O' && data1[2][1]=='O')
        return 'O';
    if (data1[0][2]=='O' && data1[1][2]=='O' && data1[2][2]=='O')
        return 'O';
    //diagonal
    if (data1[0][0]=='O' && data1[1][1]=='O' && data1[2][2]=='O')
        return 'O';
    if (data1[2][0]=='O' && data1[1][1]=='O' && data1[0][2]=='O')
        return 'O';
    return '>';
}
int main()
{
    char num1,num2,y,Y,N,n;
    int num3;
    do
    {
        cout<<"TIC TAC TOE"<<endl;
        cout<<" 1. Start"<<endl;
        cout<<" 2. Exit"<<endl;
        cin>>num3;
        system("cls");
        if(num3==1)
        {
            do
            {
                clear();
                while (1)
                {
                    
                    draw();
                    input();
                    if (win()=='X')
                    {
                        system("cls");
                        cout<<endl<<"X wins!"<<endl<<endl;

                        cout<<" Main lagi ? (y/n) ";
                        cin>>num1;
                    }
                    else if(win()=='O')
                    {
                        system("cls");
                        cout<<endl<<"O wins!"<<endl<<endl;
                        cout<<" Main lagi ? (y/n) ";
                        cin>>num1;
                    }
                    pla();
                    system("cls");
                }
                system("pause");
            } while (num1=='y' || num1=='Y');
            
                cout<<" Ingin kembali ke menu? (y/n)";
                cin>>num2;
            
        }
        else
        {
            cout<<"Terimakasih telah bermain!";
        }
                
    } while (num2=='y' || num2=='Y');
    

}

Answer 1

(data1[0][i] == ' ') && (data1[0][i] == data1[1][i]) && (data1[1][i] == data1[2][i]);

这没有任何作用！只是一串条件而已。

我怀疑你打算执行一系列作业：

data1[0][i] = ' ';
data1[0][i] = data1[1][i];
data1[1][i] = data1[2][i];

接下来，注意其中两个是从后到前的，所以：

data1[0][i] = ' ';
data1[1][i] = data1[0][i];
data1[2][i] = data1[1][i];

虽然你也可以这样写：

data1[0][i] = data1[1][i] = data1[2][i] = '';

或者，对于最佳代码（在我看来）：

data1[0][i] = ' ';
data1[1][i] = ' ';
data1[2][i] = ' ';

为什么我的 tic tac toe C++ clear board 不起作用

Why my clear board on tic tac toe C++ doesnt work

c++

tic-tac-toe