如何定义一个特定范围为"sum(x, len)"的长度？

Question

我想检查在回溯期的前半段是否至少满足一次特定条件，然后在回溯期的后半段至少再次满足一次。

我正在尝试使用下面的代码来做到这一点，如。但是我没有弄清楚如何使 len 成为一个范围。

所以我的问题是：如何使 len 成为一个范围？（低于 len 为 lenFirstHalf 和 lenSecondHalf）。

非常感谢任何帮助！

lookBack = input(title="Lookback", type=input.integer, defval=24, minval=2)
condition = close > open
lenFirstHalf = (<GREATER THAN> (lookBack/2)) and (<LESS THAN OR EQUAL TO> lookback)
lenSecondHalf = (<GREATER THAN OR EQUAL TO> 1) and (<LESS THAN OR EQUAL TO (lookback/2))

// Check if the condition is met in the FIRST half of the lookback period
triggerA = (sum(condition ? 1 : 0, lenFirstHalf)) >= 1 ? true : false
// Check if the condition is met in the SECOND half of the lookback period
triggerB = (sum(condition ? 1 : 0, lenSecondHalf)) >= 1 ? true : false

显然，那些<GREATER THAN>和<LESS THAN OR EQUAL TO>不存在，但我不知道如何将这样的范围归因于一个变量。

Answer 1

我认为这样的事情应该可行。

lookBack = input(title="Lookback", type=input.integer, defval=24, minval=2)

condition     = close > open

sumLookBack   = sum(condition ? 1 : 0, lookBack)
sumSecondHalf = sum(condition ? 1 : 0, lookBack/2)
sumFirstHalf  = sumLookBack - sumSecondHalf

// Check if the condition is met in the FIRST half of the lookback period
triggerA = sumFirstHalf >= 1 ? true : false
// Check if the condition is met in the SECOND half of the lookback period
triggerB = sumSecondHalf >= 1 ? true : false

您在 sum() 中使用的 length 用于计算从 length 柱回溯到最新柱的总和。
因此，首先计算整个长度，然后减去“后”一半，就得到“前”一半。

如何定义一个特定范围为"sum(x, len)"的长度？

How to define a specific range as the length of "sum(x, len)"?

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