如何在 VBA 中的范围内均匀分布已知数字

Question

我遇到了一个问题，我一直在尝试使用 VBA 在 range.The 中平均分配一个已知数字问题是我需要找到数字在范围尽可能彼此相等，你能帮我吗？或提供意见？

数据集如下

已知数字由红色的“TV Comodin”行给出，这是我的尝试：

    Sub Prueba()

  Columns("A:A").Select
    Set Cell = Selection.Find(What:="TV Comodín", After:=ActiveCell, LookIn:=xlFormulas, _
    LookAt:=xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
    MatchCase:=False, SearchFormat:=False)
    ActiveCell = Cell
    Cell.Select
    
    comodin = ActiveCell.Offset(0, 1).Value2

    Range("A2").Select
    Firstrow = ActiveCell.Row
    Selection.End(xlDown).Select
    Lastrow = ActiveCell.Row

    j = comodin 
While (j > 0)
        For i = 2 To Lastrow
        Range("B2").Select
        Range("B" & i) = Range("B" & i).Value + 1
        If j > 0 Then j = j - 1
        If j = 0 Then Exit For
   
    Next

Wend
          
End Sub

基本上，我的代码找到“TV Comodin”行以获得循环将在其列的每一行中加 1 乘 1 的次数，

抱歉，我对 VBA 有点陌生，顺便谢谢你。

Answer 1

这是一种方法。找到范围内的最小数字：加一。重复直到完成（例如）55 次。

Sub Prueba()
    Dim f As Range, ws As Worksheet, comodin As Long, rng As Range, m, mn
    
    Set ws = ActiveSheet
    
    Set rng = ws.Range("A2", ws.Range("A2").End(xlDown)).Offset(0, 1)
    
    Set f = ws.Columns("A").Find(What:="TV Comodín", LookIn:=xlFormulas, _
                                 LookAt:=xlWhole, MatchCase:=False)
   
    If Not f Is Nothing Then
        rng.Value = ws.Evaluate("=" & rng.Address() & "*1") 'fill empty cells with zeros
        comodin = f.Offset(0, 1).Value
        Do While comodin > 0
            mn = Application.Min(rng)
            If mn >= 100 Then Exit Do ' exit when no values are <100 
            m = Application.Match(mn, rng, 0)
            rng.Cells(m).Value = rng.Cells(m).Value + 1
            comodin = comodin - 1
        Loop
    Else
        MsgBox "not found!"
    End If
End Sub

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