pynput 代码没有给我一个简单的字符串作为键

Question

我有这个简单的 pynput 代码：

import pynput
from pynput.keyboard import Key, Listener

keys = []

def on_press(key):
    keys.append(key)
    write_file(keys)


def write_file(keys):

    allowed = ['7','9','1','3','4','5','6','q','w','e','z']
    with open('log.txt', 'w') as f:
        for key in keys:
            if key in allowed:
                # removing ''
                k = str(key).replace("'", "")
                f.write(k)

                f.write(',')

def on_release(key):

    print('{0} released'.format(key))
    if key == Key.esc:
        # Stop listener
        return False


with Listener(on_press = on_press,
        on_release = on_release) as listener:

    listener.join()

当我运行并在键盘上输入 7 时，我希望它会将 7 写入 log.txt，因为它在允许列表中。但事实并非如此。我使用 import pdb 和 pdb.set_trace() 跟踪它，当我手动输入

'7' in allowed

我得到一个 True

但是当我使用

key in allowed

即使键是“7”，我也得到了一个 False。我怀疑这与类型有关，因为当我使用

type(key)

我明白了

<class 'pynput.keyboard._xorg.KeyCode'>

所以我想我必须让 key 成为一个普通而无聊的字符串。但是

str(key)

仍然不会说它在允许列表中。

我尝试查看有关 KeyCode 的 pynput 文档，但我认为这对我没有帮助。也许其他人知道如何进行这项工作？

Answer 1

你要比较

key.char == '7'

但是当 key 没有 .char 时它会给出错误 - 即 Ctrl、Alt、Shift 等，甚至 Space - 比较

更安全

key == KeyCode.from_char('7')

from pynput.keyboard import Listener, Key, KeyCode


def on_press(key):
    try:
        print('from_char:', key == KeyCode.from_char('7'))
        print('key.char :', key.char == '7')
    except Exception as ex:
        print('Error:', ex)


def on_release(key):

    #print('{0} released'.format(key))
    if key == Key.esc:
        # Stop listener
        return False


with Listener(on_press=on_press, on_release=on_release) as listener:
    listener.join()

编辑：

from pynput.keyboard import Listener, Key, KeyCode


#allowed = [KeyCode.from_char('7'), KeyCode.from_char('9')]
#allowed = [KeyCode.from_char(char) for char in ['7','9','1','3','4','5','6','q','w','e','z']]
allowed = [KeyCode.from_char(char) for char in '7913456qwez']
    
def on_press(key):
    try:
        print('allowed:', key in allowed)
    except Exception as ex:
        print('Error:', ex)


def on_release(key):

    #print('{0} released'.format(key))
    if key == Key.esc:
        # Stop listener
        return False


with Listener(on_press=on_press, on_release=on_release) as listener:
    listener.join()

pynput 代码没有给我一个简单的字符串作为键

pynput code doesn't give me a simple string as a key

python

types

pynput