JavaScript 开关中的同步条件
The simultaneous criteria in JavaScript switch
除了像“28 或 29 天”这样的写法,我们如何添加闰年检查来切换,以获得 2000 年的 29 天?
var month = "Feb";
var year = 2000;
switch(month) {
case "Apr": case "Jun": case "Sep": case "Nov":
console.log("30 days."); break;
case "Feb":
console.log("28 or 29 days."); break;
default: console.log("31 days.");
}
希望对您有所帮助。代码应该是自我解释的。请告诉我。
function isLeapYear(year) {
return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
}
function getMonthLength(month, year) {
switch(month) {
case "Apr": case "Jun": case "Sep": case "Nov":
return 30;
case "Feb":
return isLeapYear(year) ? 29 : 28;
default:
return 31;
}
}
console.log(getMonthLength('Feb', 2000));
console.log(getMonthLength('Jan', 2001));
console.log(getMonthLength('Feb', 2001));
console.log(getMonthLength('Sep', 2001));
知道2020年是闰年
写一个这样的函数
var findLeap = ()=> {
var dateYear = new Date().getFullYear();
var leap = dateYear - 2020
if (leap % 4 == 0){
console.log('Its another Leap year')
}else{
console.log('Its NOT a Leap year')
}
}
除了像“28 或 29 天”这样的写法,我们如何添加闰年检查来切换,以获得 2000 年的 29 天?
var month = "Feb";
var year = 2000;
switch(month) {
case "Apr": case "Jun": case "Sep": case "Nov":
console.log("30 days."); break;
case "Feb":
console.log("28 or 29 days."); break;
default: console.log("31 days.");
}
希望对您有所帮助。代码应该是自我解释的。请告诉我。
function isLeapYear(year) {
return ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
}
function getMonthLength(month, year) {
switch(month) {
case "Apr": case "Jun": case "Sep": case "Nov":
return 30;
case "Feb":
return isLeapYear(year) ? 29 : 28;
default:
return 31;
}
}
console.log(getMonthLength('Feb', 2000));
console.log(getMonthLength('Jan', 2001));
console.log(getMonthLength('Feb', 2001));
console.log(getMonthLength('Sep', 2001));
知道2020年是闰年 写一个这样的函数
var findLeap = ()=> {
var dateYear = new Date().getFullYear();
var leap = dateYear - 2020
if (leap % 4 == 0){
console.log('Its another Leap year')
}else{
console.log('Its NOT a Leap year')
}
}