如何在 Spark 中获取 spark.ml NaiveBayes 概率向量而不是 [0-1] class？

Question

我正在研究 NaiveBayes 分类器，我可以使用经过训练的模型预测单个数据点的值，但我想获得概率值。

数据分为两个类而已。和预测函数 returns 0 或 1.

import org.apache.log4j.{Level, Logger}
import org.apache.spark.ml.classification.{NaiveBayes, NaiveBayesModel}
import org.apache.spark.ml.feature.LabeledPoint
import org.apache.spark.ml.linalg.Vectors
import org.apache.spark.sql.SparkSession

object Test {
  def main(args: Array[String]): Unit = {
    Logger.getLogger("org").setLevel(Level.OFF)
    Logger.getLogger("akka").setLevel(Level.OFF)
    val spark = SparkSession.builder.appName("Test").master("local[4]").getOrCreate
    val dataset = spark.read.option("inferSchema", "true").csv("data/labelled.csv").toDF()

    import spark.sqlContext.implicits._
    val output = dataset.map(row => {
      LabeledPoint(row.getInt(2), Vectors.dense( row.getInt(0) , row.getInt(1)))
    })
    val Array(training, test) =  output.randomSplit(Array(0.7, 0.3),seed = 11L)
    training.cache()

    val model : NaiveBayesModel = new NaiveBayes().fit(training)
    val speed = 110
    val hour  = 11
    val label1 : Double =  model.predict(Vectors.dense(speed,hour))
    // UPDATE
    val label = model.predictProbability(Vectors.dense(speed,hour)) // This not work and raise error[1]
  }
}

[1] 使用model.predictProbability

时出现的错误

Error:(24, 23) method predictProbability in class ProbabilisticClassificationModel cannot be accessed in org.apache.spark.ml.classification.NaiveBayesModel Access to protected method predictProbability not permitted because enclosing object Test is not a subclass of class ProbabilisticClassificationModel in package classification where target is defined val label = model.predictProbability(Vectors.dense(speed,hour))

Answer 1

经过多次研究，我没有在 spark.ml 库中找到此功能，但我能够使用 spark.mllib 做到这一点，代码应修改为

import org.apache.log4j.{Level, Logger}
// Import NaiveBayes, NaiveBayesModel from mlib 
import org.apache.spark.mllib.classification.{NaiveBayes, NaiveBayesModel}
// Import LabeledPoint, Vectors from mlib to create dataset
import org.apache.spark.mllib.regression.LabeledPoint
import org.apache.spark.mllib.linalg.Vectors
import org.apache.spark.sql.SparkSession

object Test {
  def main(args: Array[String]): Unit = {
    Logger.getLogger("org").setLevel(Level.OFF)
    Logger.getLogger("akka").setLevel(Level.OFF)
    val spark = SparkSession.builder.appName("Test").master("local[4]").getOrCreate
    val dataset = spark.read.option("inferSchema","true").csv("data/labelled.csv").toDF()

    import spark.sqlContext.implicits._
    // using mllib.regression.LabeledPoint & mllib.linalg.Vectors then transform DF to JavaRDD
    val output = dataset.map(row => {
      LabeledPoint(row.getInt(2), Vectors.dense( row.getInt(0) , row.getInt(1)))
    }).toJavaRDD
    
    val Array(training, test) =  output.randomSplit(Array(0.7, 0.3),seed = 11L)
    training.cache()
    //Using Run instead of fit method
    val model : NaiveBayesModel = new NaiveBayes().run(training)
    val speed = 110
    val hour  = 11
    // return predict value
    val label1 : Double =  model.predict(Vectors.dense(speed,hour))
    // return array of predict Probabilities `each class Probability`
    val testLabel = model.predictProbabilities(Vectors.dense(speed,hour))
  }
}

如何在 Spark 中获取 spark.ml NaiveBayes 概率向量而不是 [0-1] class？

How to get spark.ml NaiveBayes probability vector not [0-1] class in Spark?

scala

machine-learning

apache-spark

naivebayes

apache-spark-ml