Python 3.4: 将列表中的“0x”替换为“\x”

Question

您好，我想在此列表中用“\x”替换“0x”：

['0x50', '0x0', '0x0', '0x0']

我用这个列表理解试过了：

result = ['0x50', '0x0', '0x0', '0x0']
result = [x.replace("0x","\x") for x in result]

但是它给了我这个错误：

(unicode error)"unicodeescape" codex cant decode byte in position 0-1: truncated \xXX escape

现在如何更改“0x”和“\x”？

Answer 1

将其设为原始字符串，如

>>> l = ['0x50', '0x0', '0x0', '0x0']
>>> [i.replace('0x',r'\x') for i in l]
['\x50', '\x0', '\x0', '\x0']

或双转义 \ 如

>>> [i.replace('0x','\x') for i in l]
['\x50', '\x0', '\x0', '\x0']

Python 3.4: replace "0x" with "\x" in a List