ios

Question

我正在使用以下代码进行分享 sheet:

let url = "https://somelink.com"
let image = "https://myserver/an_image.png"
let text = "Join now!"
    
let shareSheetVC = UIActivityViewController(activityItems: [image, url, text], applicationActivities: nil)
    
shareSheetVC.popoverPresentationController?.sourceView = sender
shareSheetVC.popoverPresentationController?.sourceRect = sender.frame
present(shareSheetVC, animated: true)

我想要的是这样的：

然而，当我分享时，我得到

https://somelink.com https:///myserver/an_image.png 立即加入！

我如何格式化它来完成类似示例的操作？

Answer 1

这是使用 UIActivityViewController

分享 Text、Image 和 URL 的基本示例

 let text = "Join Now!"
 let image =  UIImage(named: "your_image")
 let myWebsite = URL(string: "https://somelink.com")
 let shareAll = [text , image! , myWebsite]
 let activityViewController = UIActivityViewController(activityItems: shareAll, applicationActivities: nil)
 activityViewController.popoverPresentationController?.sourceView = self.view 
 activityViewController.popoverPresentationController?.sourceRect = sender.frame

 self.present(activityViewController, animated: true, completion: nil)

希望你明白。

Answer 2

或者，您可以从不同的角度解决这个问题，并尝试通过添加以下内容来修复您的网页：

<meta property="og:image" content="https://myserver/an_image.png">
<title>Join now!</title>

这些标签将默认从 UIActivityViewController.

中获取

ios - 格式化分享的信息share sheet

ios - format the information shared with share sheet

swift

ios-sharesheet