如何为 Sql 服务器行中一系列不断变化的序列号生成序列号

Question

我需要第一个 TSL 发件人与后续供应商的日期差异，以及下一个 TSL 与下一个后续发件人作为供应商的日期差异

期望的输出

Answer 1

因此您需要 TSL 更改为 Vendor 的天数差异。您可以使用如下解析函数：

select t.*,
       case when sender = 'Vendor' 
            then DATEDIFF(hour, date, first_value(date) over (partition by rn - rn_s order by date) ) / 24.0 end as diff
  from
(select t.*,
       row_number() over (order by date) as rn,
       row_number() over (partition by sender order by date) as rn_s
  from yout_table t) t

Answer 2

您可以通过计算每行上或之后的 'Vendor' 值的数量来为行分配分组。然后每个分组以 'Vendor' 结尾，您可以在该组中使用 window 函数：

select t.*,
       (case when sender = 'vendor'
             then datediff(second,
                           min(date) over (partition by grp),
                           max(date) over (partition by grp)
                          ) / (24 * 60 * 60.0)
        end) as diff
from (select t.*,
             sum(case when sender = 'Vendor' then 1 else 0 end) over (order by id desc) as grp
      from t
     ) t;

如何为 Sql 服务器行中一系列不断变化的序列号生成序列号

How to generate a serial number to series of constant change in Sql Server rows

sql

sql-server-2012