比较每隔一行的时间差

Question

我正在尝试确定对每隔一行使用 AR_Event_Creation_Date_Time 之间的时间长度（以天为单位）。例如，第 1 行和第 2 行、第 3 行和第 4 行、第 5 行和第 6 行之间的天数等。换句话说，每个偶数行都有一个天数值，每个奇数行都有一个 NULL。如果每个借款人编号只有两行，我下面的代码就可以工作，但当超过两行时就会下降。在结果中，注意 1002092539

的变化

SELECT  Borrower_Number, 
Workgroup_Name,
FORMAT(AR_Event_Creation_Date_Time,'d','en-us') AS Tag_Date,
Usr_Usrnm,
DATEDIFF(day, LAG(AR_Event_Creation_Date_Time,1) OVER(PARTITION BY 
Borrower_Number Order By Borrower_Number), AR_Event_Creation_Date_Time) Diff
FROM Control_Mail

Answer 1

您需要添加行号。此外，您的 partition by 是不确定的：

SELECT  Borrower_Number, 
    Workgroup_Name,
    FORMAT(AR_Event_Creation_Date_Time,'d','en-us') AS Tag_Date,
    Usr_Usrnm,
    DATEDIFF(day, LAG(AR_Event_Creation_Date_Time,1) OVER(PARTITION BY Borrower_Number, (rn - 1) / 2 ORDER BY AR_Event_Creation_Date_Time),
    AR_Event_Creation_Date_Time) Diff
FROM (
    SELECT *,
    ROW_NUMBER() OVER (PARTITION BY Borrower_Number ORDER BY AR_Event_Creation_Date_Time) AS rn
    FROM Control_Mail
) C
```

比较每隔一行的时间差

Comparing time difference for every other row

sql

sql-server

sql-server-2017