如何将可变数据传递到 libcurl post 正文中？

Question

我在使用 libcurl 时将变量值传递到 POST 正文时遇到问题。这是我的代码：

#include "curl/curl.h"

char *fullname ="morpheus";
char *role = "leader";

CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl) {
  curl_easy_setopt(curl, CURLOPT_CUSTOMREQUEST, "POST");
  curl_easy_setopt(curl, CURLOPT_URL, "https://reqres.in/api/users");
  curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION, 1L);
  curl_easy_setopt(curl, CURLOPT_DEFAULT_PROTOCOL, "https");
  struct curl_slist *headers = NULL;
  headers = curl_slist_append(headers, "Content-Type: text/json");
  curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
  const char *data = "{\"name\": \"${fullname}\" ,\"job\":\"${role}\"}";
  curl_easy_setopt(curl, CURLOPT_POSTFIELDS, data);
  curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, function_pt);
  res = curl_easy_perform(curl);
}
curl_easy_cleanup(curl);

Answer 1

您将变量本身的名称作为字符串传递。您必须连接值，而不是名称。

#include "curl/curl.h"

char *fullname ="morpheus";
char *role = "leader";

CURL *curl;
CURLcode res;
curl = curl_easy_init();
if(curl) {
  curl_easy_setopt(curl, CURLOPT_CUSTOMREQUEST, "POST");
  curl_easy_setopt(curl, CURLOPT_URL, "https://reqres.in/api/users");
  curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION, 1L);
  curl_easy_setopt(curl, CURLOPT_DEFAULT_PROTOCOL, "https");
  struct curl_slist *headers = NULL;
  headers = curl_slist_append(headers, "Content-Type: text/json");
  curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headers);
  char *data = "{\"name\":";
  strcat(data, fullname);
  strcat(data, ",\"job\":\");
  strcat(data, role);;
  strcat(data, "\"}");
  curl_easy_setopt(curl, CURLOPT_POSTFIELDS, data);
  curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, function_pt);
  res = curl_easy_perform(curl);
}
curl_easy_cleanup(curl);

这当然不是最干净的方法，但它会奏效。

如何将可变数据传递到 libcurl post 正文中？

How do I pass variable data into libcurl post body?

c

curl

libcurl