特征默认方法中的多个自我借用
multiple self borrows within trait default methods
我 运行 遇到借用检查器的问题。我有一个特征 (Physics
),它有 getter(例如 velocity
)和 setter(例如 velocity_mut
)。它还具有使用 getter 和 setter 的默认方法 accelerate
和 apply_force
。为什么多次借用不好,解决这个问题的方法是什么?这是一条错误消息:
13:18 rustc error cannot borrow `*self` as immutable because it is also borrowed as mutable
immutable borrow occurs here
12:11 rustc hint mutable borrow occurs here
12:11 rustc hint argument requires that `*self` is borrowed for `'static`
use gdnative::prelude::*;
// Running into issues with the borrow checker
trait Physics {
fn apply_force(&mut self, force: &mut Vector2, truncate: bool) {
let max_force = self.max_force();
if force.square_length() > max_force * max_force && truncate {
*force = force.normalize() * max_force;
}
let a = self.acceleration_mut();// Line 12
*a += *force / self.mass();//Line 13
self.accelerate(truncate);
}
fn accelerate(&mut self, truncate: bool) {
let v = self.velocity_mut();
*v += self.acceleration();
let max_speed = self.max_speed();
if v.square_length() > max_speed * max_speed && truncate {
*v = v.normalize() * max_speed;
}
}
fn velocity(&self) -> Vector2;
fn velocity_mut(&mut self) -> &mut Vector2;
fn acceleration(&self) -> Vector2;
fn acceleration_mut(&mut self) -> &mut Vector2;
fn max_speed(&self) -> f32;
fn max_speed_mut(&mut self) -> &mut f32;
fn max_force(&self) -> f32;
fn max_force_mut(&mut self) -> &mut f32;
fn mass(&self) -> f32;
fn mass_mut(&mut self) -> &mut f32;
}
struct Actor {
velocity: Vector2,
acceleration: Vector2,
max_speed: f32,
max_force: f32,
mass: f32
}
impl Physics for Actor {
fn velocity(&self) -> Vector2 {
self.velocity
}
fn velocity_mut(&mut self) -> &mut Vector2 {
&mut self.velocity
}
fn acceleration(&self) -> Vector2 {
self.acceleration
}
fn acceleration_mut(&mut self) -> &mut Vector2 {
&mut self.acceleration
}
fn mass(&self) -> f32 {
self.mass
}
fn mass_mut(&mut self) -> &mut f32 {
&mut self.mass
}
fn max_speed(&self) -> f32 {
self.max_speed
}
fn max_speed_mut(&mut self) -> &mut f32 {
&mut self.max_speed
}
fn max_force(&self) -> f32 {
self.max_force
}
fn max_force_mut(&mut self) -> &mut f32 {
&mut self.max_force
}
}
fn main() {
}
在存在可变借用的情况下不能不可变借用的原因是,否则您可以使用可变借用来修改由不可变借用表示的基础数据。由于不可变借用(显然)不应该改变,借用检查器不能承担风险(即使你“知道”可变借用不会影响不可变借用)。
在这种情况下,我相信您可以通过在调用 self.acceleration_mut()
之前将 self.mass()
分配给本地来解决这个问题
let mass = self.mass();
let a = self.acceleration_mut();
*a += *force / mass;
由于 mass 只是一个 f32
,它被复制到 return,所以不可变借用将在下一行之前完成。
由于“吸气剂”return 拥有值,另一种设计是使用局部变量来计算结果,并仅在末尾分配它(通过可变引用):
fn apply_force(&mut self, force: &mut Vector2, truncate: bool) {
let max_force = self.max_force();
if force.square_length() > max_force * max_force && truncate {
*force = force.normalize() * max_force;
}
let mut a = self.acceleration(); // Line 12
a += *force / self.mass(); //Line 13
*self.acceleration_mut() = a;
self.accelerate(truncate);
}
fn accelerate(&mut self, truncate: bool) {
let mut v = self.velocity();
v += self.acceleration();
let max_speed = self.max_speed();
if v.square_length() > max_speed * max_speed && truncate {
v = v.normalize() * max_speed;
}
*self.velocity_mut() = v;
}
避免使用局部变量(例如,如果您假设基础值是克隆的,并且这是昂贵的),是很棘手的,因为很难通过可变引用锁定方法的整个长度(或左右)管理。
我 运行 遇到借用检查器的问题。我有一个特征 (Physics
),它有 getter(例如 velocity
)和 setter(例如 velocity_mut
)。它还具有使用 getter 和 setter 的默认方法 accelerate
和 apply_force
。为什么多次借用不好,解决这个问题的方法是什么?这是一条错误消息:
13:18 rustc error cannot borrow `*self` as immutable because it is also borrowed as mutable
immutable borrow occurs here
12:11 rustc hint mutable borrow occurs here
12:11 rustc hint argument requires that `*self` is borrowed for `'static`
use gdnative::prelude::*;
// Running into issues with the borrow checker
trait Physics {
fn apply_force(&mut self, force: &mut Vector2, truncate: bool) {
let max_force = self.max_force();
if force.square_length() > max_force * max_force && truncate {
*force = force.normalize() * max_force;
}
let a = self.acceleration_mut();// Line 12
*a += *force / self.mass();//Line 13
self.accelerate(truncate);
}
fn accelerate(&mut self, truncate: bool) {
let v = self.velocity_mut();
*v += self.acceleration();
let max_speed = self.max_speed();
if v.square_length() > max_speed * max_speed && truncate {
*v = v.normalize() * max_speed;
}
}
fn velocity(&self) -> Vector2;
fn velocity_mut(&mut self) -> &mut Vector2;
fn acceleration(&self) -> Vector2;
fn acceleration_mut(&mut self) -> &mut Vector2;
fn max_speed(&self) -> f32;
fn max_speed_mut(&mut self) -> &mut f32;
fn max_force(&self) -> f32;
fn max_force_mut(&mut self) -> &mut f32;
fn mass(&self) -> f32;
fn mass_mut(&mut self) -> &mut f32;
}
struct Actor {
velocity: Vector2,
acceleration: Vector2,
max_speed: f32,
max_force: f32,
mass: f32
}
impl Physics for Actor {
fn velocity(&self) -> Vector2 {
self.velocity
}
fn velocity_mut(&mut self) -> &mut Vector2 {
&mut self.velocity
}
fn acceleration(&self) -> Vector2 {
self.acceleration
}
fn acceleration_mut(&mut self) -> &mut Vector2 {
&mut self.acceleration
}
fn mass(&self) -> f32 {
self.mass
}
fn mass_mut(&mut self) -> &mut f32 {
&mut self.mass
}
fn max_speed(&self) -> f32 {
self.max_speed
}
fn max_speed_mut(&mut self) -> &mut f32 {
&mut self.max_speed
}
fn max_force(&self) -> f32 {
self.max_force
}
fn max_force_mut(&mut self) -> &mut f32 {
&mut self.max_force
}
}
fn main() {
}
在存在可变借用的情况下不能不可变借用的原因是,否则您可以使用可变借用来修改由不可变借用表示的基础数据。由于不可变借用(显然)不应该改变,借用检查器不能承担风险(即使你“知道”可变借用不会影响不可变借用)。
在这种情况下,我相信您可以通过在调用 self.acceleration_mut()
self.mass()
分配给本地来解决这个问题
let mass = self.mass();
let a = self.acceleration_mut();
*a += *force / mass;
由于 mass 只是一个 f32
,它被复制到 return,所以不可变借用将在下一行之前完成。
由于“吸气剂”return 拥有值,另一种设计是使用局部变量来计算结果,并仅在末尾分配它(通过可变引用):
fn apply_force(&mut self, force: &mut Vector2, truncate: bool) {
let max_force = self.max_force();
if force.square_length() > max_force * max_force && truncate {
*force = force.normalize() * max_force;
}
let mut a = self.acceleration(); // Line 12
a += *force / self.mass(); //Line 13
*self.acceleration_mut() = a;
self.accelerate(truncate);
}
fn accelerate(&mut self, truncate: bool) {
let mut v = self.velocity();
v += self.acceleration();
let max_speed = self.max_speed();
if v.square_length() > max_speed * max_speed && truncate {
v = v.normalize() * max_speed;
}
*self.velocity_mut() = v;
}
避免使用局部变量(例如,如果您假设基础值是克隆的,并且这是昂贵的),是很棘手的,因为很难通过可变引用锁定方法的整个长度(或左右)管理。