使用泛型的 ZIO Mock 方法

Question

我正在尝试模拟具有通用方法的服务，但我不知道如何在模拟中定义效果。通用效果甚至可以工作吗？有什么解决方法吗？

服务：

object AService {

  type AService = Has[Service]

  trait Service {
    def add(n1: Int, n2: Int): Task[Int]
    def foo[A](n1: A, n2: A): Task[A]
  }

  def live: ULayer[Has[Service]] = ...
}

模拟：

object AServiceMock extends Mock[AService] {

  object Add        extends Effect[(Int, Int), Nothing, Int]
  object Foo[T]     extends Effect[(T, T), Nothing, T]       // <- Can I make something like this work?

  override protected[test] val compose = ZLayer.fromService {proxy =>
    new AService.Service {
      override def add(n1: Int, n2: Int): Task[Int] = proxy(Add, n1, n2)

      override def foo[T](n1: T, n2: T): Task[T] = proxy(Foo, n1, n2)
    }
  }
}

PS：我也尝试过 @mockable[AService.Service]，但我收到：“宏扩展期间出现异常：需要标识符，但 $XMLSTART$< 找到了”

谢谢

Answer 1

已解决。答案在 ZIO documentation

def foo[A: zio.Tag](n1: A, n2: A): Task[A]

----------------

object AServiceMock extends Mock[AService] {

  object Add extends Effect[(Int, Int), Nothing, Int]
  object Foo extends Poly.Effect.InputOutput[Nothing]

  val compose: URLayer[Has[mock.Proxy], AService] = ZLayer.fromService { proxy =>
    new AService.Service {
      override def add(n1: Int, n2: Int): Task[Int] = proxy(Add, n1, n2)

      override def foo[A: Tag](n1: A, n2: A): Task[A] = proxy(Foo.of[(A, A), A], n1, n2)
    }
  }
}

使用泛型的 ZIO Mock 方法

ZIO Mock method that works with generics

scala

zio

zio-test