删除电报机器人发送的传出消息（电报，python）

Question

我卡在了我的代码中，因为我不知道如何 input/derive 我的机器人转发的外发消息的 message_id。

背景：这只是我随后将集成到主代码中的代码的一部分。在这里，我正在测试转发消息+删除消息的功能。我能够成功地将它们转发出去，但我一直坚持删除它们。我能够提供 chat_id 的输入，但无法为要删除的 message_id 提供输入。有没有办法做到这一点，尤其是当我要集成到我的主脚本中时，它可以管理几个组。请帮助我的菜鸟。谢谢！

我的脚本：

import logging
from telegram import ReplyKeyboardMarkup, ReplyKeyboardRemove, Update
from telegram.ext import (
    Updater,
    CommandHandler,
    MessageHandler,
    Filters,
    ConversationHandler,
    CallbackContext,
)

TOKEN = "PUT TOKEN HERE" #INPUT HERE 

# Enable logging
logging.basicConfig(
    format='%(asctime)s - %(name)s - %(levelname)s - %(message)s', level=logging.INFO)

logger = logging.getLogger(__name__)

MSG, DELETE_MSG = range(2)


def start(update: Update, context: CallbackContext) -> int:
    update.message.reply_text(
        'Hi! Please post the message you would like to share:')
    return MSG


def send(update: Update, context: CallbackContext) -> int:
    user = update.message.from_user
    logger.info("Message of %s: %s", user.first_name, update.message.text)
    print(update.message.message_id)
    send = update.message.forward(chat_id= 'PUT CHAT ID OF OUTGOING GROUP HERE') #INPUT HERE 
    update.message.reply_text("Please delete")

    return DELETE_MSG

def delete_msg(update: Update, context: CallbackContext) -> int:
    user = update.message.from_user
    logger.info("edit of %s: %s", user.first_name, update.message.text) 
    
    update.message.delete(chat_id='PUT CHAT ID OF OUTGOING GROUP HERE', 
                        message_id='IM STUCK HERE') #INPUT HERE 
    return ConversationHandler.END


def cancel(update: Update, context: CallbackContext) -> int:
    user = update.message.from_user
    logger.info("User %s canceled the conversation.", user.first_name)
    update.message.reply_text('Bye! I hope we can talk again some day.', reply_markup=ReplyKeyboardRemove())
    return ConversationHandler.END


def main() -> None:
    updater = Updater(TOKEN, use_context=True)

    dispatcher = updater.dispatcher
    conv_handler = ConversationHandler(
        entry_points=[CommandHandler('start', start)],
        states={
            MSG: [MessageHandler(~Filters.command, send)],
            DELETE_MSG: [MessageHandler(~Filters.command, delete_msg)]
        },
        fallbacks=[CommandHandler('cancel', cancel)],
    )

    dispatcher.add_handler(conv_handler)
    
    updater.start_polling()
    updater.idle()


if __name__ == '__main__':
    main()

Answer 1

update.message.reply_text("Please delete") 必须是一个变量，然后，您将能够 context.bot.deleteMessage 其 message_id。就像这样：

must_delete = update.message.reply_text("Please delete")
context.bot.deleteMessage (message_id = must_delete.message_id,
                           chat_id = update.message.chat_id)

试一试，让我知道这是否适合你！

删除电报机器人发送的传出消息（电报，python）

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