如何使用 Node.js 检索内容中不包含特定字符串的文件

Question

我的 directory 中有一个 strings 的 array 代表文件 paths。我创建了一个名为 readFileContent 的 function 来读取文件内容，而另一个 function 用于在文件内容中查找某个 string。现在我想创建一个新的 array 文件路径，其中包含所述 string。但是，我没有让它工作。这是我的代码：

const allFilePaths = [
  '/path/to/file1.js',
  '/slighty/longer/path/to/file2.js',
  '/way/slighty/longer/path/to/file3.js',
  '/path/to/file4.js',
];

// utility function to check if str param doesn't contains "https" string
const getUrl = str => !str.match(/https:\s*([^;]+)\n/);

// utility function to read a file - the file param represent a file path
const readFileContent = file => {
  return new Promise((resolve, reject) => {
    fs.readFile(file, 'utf8', (err, data) => {
      if (err) return reject(err);
      return resolve(data);
    });
  });
};

(async () => {
  // functions to return all file that don't contain a url, I get error: str.match is not a function
  const allFileWithoutUrls = await str.match is not a function.map(file =>
    getUrl(readFileContent(file)) ? file : null
})();

有什么问题？

Answer 1

尝试 .filter 方法而不是 .map。 .filter 方法将 return 一个新数组，其中每个项目取决于您 return 回调函数中的真值或假值。

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

const allFilePaths = [
  "/path/to/file1.js",
  "/slighty/longer/path/to/file2.js",
  "/way/slighty/longer/path/to/file3.js",
  "/path/to/file4.js",
];

// utility function to check if str param doesn't contains "https" string
const getUrl = (str) => !str.match(/https:\s*([^;]+)\n/);

// utility function to read a file - the file param represent a file path
const readFileContent = (file) => {
  return new Promise((resolve, reject) => {
    fs.readFile(file, "utf8", (err, data) => {
      if (err) return reject(err);
      return resolve(data);
    });
  });
};

(async () => {
  // functions to return all file that don't contain a url, I get error: str.match is not a function
  const promises = allFilePaths.map(async (filePath) => {
    const contents = await readFileContent(filePath);
    return { contents, filePath };
  });
  const contents = await Promise.all(promises);
  const allFileWithoutUrls = contents
    .filter(({ contents }) => getUrl(contents))
    .map(({ filePath }) => filePath);
  console.log(allFileWithoutUrls);
})();

如何使用 Node.js 检索内容中不包含特定字符串的文件

How retrieve files that don't contain a certain string in their content using Node.js

javascript

arrays

path

fs

node.js