Sharepoint 在线：使用@currentField.x 时捕获索引错误
Sharepoint online: catch index errors when using @currentField.x
我正在尝试验证列的输入。输入必须是 123-45.678.901ab.
模式
我最接近的是使用 JSON 格式：
{
"$schema": "https://developer.microsoft.com/json-schemas/sp/v2/column-formatting.schema.json",
"elmType": "div",
"txtContent": "@currentField",
“风格”： {
“背景色”：“=if(@currentField.length>13,if((@currentField.0>='0')&&(@currentField.0<='9')&&(@currentField.1 >='0')&&(@currentField.1<='9')&&(@currentField.2>='0')&&(@currentField.2<='9')&&(@currentField.3== '-')&&(@currentField.4>='0')&&(@currentField.4<='9')&&(@currentField.5>='0')&&(@currentField.5<='9 ')&&(@currentField.6=='.')&&(@currentField.7>='0')&&(@currentField.7<='9')&&(@currentField.8>='0') &&(@currentField.8<='9')&&(@currentField.9>='0')&&(@currentField.9<='9')&&(@currentField.10=='.')&&( @currentField.11>='0')&&(@currentField.11<='9')&&(@currentField.12>='0')&&(@currentField.12<='9')&&(@currentField .13>='0')&&(@currentField.13<='9'), if(@currentField.length>14,if((@currentField.14>='a')&&(@ currentField.14<='z')||(@currentField.14>='A')&&(@currentField.14<='Z'), if(@currentField.length> 15，如果（（@currentField.15>='a'）&&（@currentField.15<='z'）||（@currentField.15>='A'）&&（@currentField .15<='Z'),'green', 'red'), 'red'),'red'),'red'),'red' ),'red')"
}
}
enter image description here
问题是，如果输入少于 16 个字符，我的整个公式就会崩溃（既不是绿色也不是红色）。我希望通过在访问 @currentField.15 之前调用 if(@currentField.length>15) 来防止这种情况发生。如果输入太短，是否有正确的方法来使用 @currentField.X 而不会崩溃？
您可以尝试以下方法，使用 substring(@currentField, 15, 16) 而不是 @currentField.15
if(@currentField.length>15,if((substring(@currentField, 15, 16)>='a')&&(substring(@currentField, 15, 16)<='z')||(substring(@currentField, 15, 16)>='A')&&(substring(@currentField, 15, 16)<='Z')
我正在尝试验证列的输入。输入必须是 123-45.678.901ab.
模式我最接近的是使用 JSON 格式：
{ "$schema": "https://developer.microsoft.com/json-schemas/sp/v2/column-formatting.schema.json", "elmType": "div", "txtContent": "@currentField", “风格”： { “背景色”：“=if(@currentField.length>13,if((@currentField.0>='0')&&(@currentField.0<='9')&&(@currentField.1 >='0')&&(@currentField.1<='9')&&(@currentField.2>='0')&&(@currentField.2<='9')&&(@currentField.3== '-')&&(@currentField.4>='0')&&(@currentField.4<='9')&&(@currentField.5>='0')&&(@currentField.5<='9 ')&&(@currentField.6=='.')&&(@currentField.7>='0')&&(@currentField.7<='9')&&(@currentField.8>='0') &&(@currentField.8<='9')&&(@currentField.9>='0')&&(@currentField.9<='9')&&(@currentField.10=='.')&&( @currentField.11>='0')&&(@currentField.11<='9')&&(@currentField.12>='0')&&(@currentField.12<='9')&&(@currentField .13>='0')&&(@currentField.13<='9'), if(@currentField.length>14,if((@currentField.14>='a')&&(@ currentField.14<='z')||(@currentField.14>='A')&&(@currentField.14<='Z'), if(@currentField.length> 15，如果（（@currentField.15>='a'）&&（@currentField.15<='z'）||（@currentField.15>='A'）&&（@currentField .15<='Z'),'green', 'red'), 'red'),'red'),'red'),'red' ),'red')" } }
enter image description here
问题是，如果输入少于 16 个字符，我的整个公式就会崩溃（既不是绿色也不是红色）。我希望通过在访问 @currentField.15 之前调用 if(@currentField.length>15) 来防止这种情况发生。如果输入太短，是否有正确的方法来使用 @currentField.X 而不会崩溃？
您可以尝试以下方法，使用 substring(@currentField, 15, 16) 而不是 @currentField.15
if(@currentField.length>15,if((substring(@currentField, 15, 16)>='a')&&(substring(@currentField, 15, 16)<='z')||(substring(@currentField, 15, 16)>='A')&&(substring(@currentField, 15, 16)<='Z')