从动态获取文件夹名称 URL php

Question

我的URL可能在关注，

1) www.steptoinstall.com

2) www.steptoinstall.com/folder1

3) www.steptoinstall.com/folder1/index.php

4) www.steptoinstall.com/folder1/folder2

5) www.steptoinstall.com/folder1/folder2/

6) www.steptoinstall.com/folder1/folder2/index.php

7) www.steptoinstall.com/folder1/folder2/index.php?id=12

但我想要最后一个文件夹名称，例如

1) none

2) 文件夹 1

3) 文件夹 1

4) 文件夹 2

5) 文件夹 2

6) 文件夹2

7) 文件夹 2

下面我用了，没用

<?php
  $url = $_SERVER['REQUEST_URI'];
  print_r(dirname($url));
?>

如何在 PHP 而不是 .htaccess 中获得此输出？

Answer 1

也许这对你有用

<?php
   $urls = array(
      'http://www.steptoinstall.com',
       'http://www.steptoinstall.com/folder1',
       'http://www.steptoinstall.com/folder1/folder2/index.php?id=12'
   );

// The Function for your work
function getFolder($url) {
    $res = parse_url($url);
    if(!isset($res['path'])) {
        return false;
    }
    $res = explode('/',$res['path']);
    $out = false;
    foreach($res as $p) {
        if(!empty($p) && strpos($p,'.')===false) $out = $p;
    }
    return $out;
}

// Testing
foreach($urls as $url) {
   var_dump(getFolder($url));

}

Answer 2

如果我正确理解你的问题，你可以使用以下自定义函数

function get_arg() {
   $arguments = array();
   $path = $_SERVER['REQUEST_URI'];
   if (isset($path)) {
      $arguments = explode('/', $path);
   }
   $url_len = count($arguments);
   return ($arguments[$url_len - 2]) ? $arguments[$url_len - 2] : 'none';
 }

希望对您有所帮助。

Answer 3

我使用了正则表达式：

<?php
$data = array(
'www.steptoinstall.com',
'www.steptoinstall.com/folder1',
'www.steptoinstall.com/folder1/index.php',
'www.steptoinstall.com/folder1/folder2',
'www.steptoinstall.com/folder1/folder2/',
'www.steptoinstall.com/folder1/folder2/index.php',
'www.steptoinstall.com/folder1/folder2/index.php?id=12',
);

foreach($data as $url)
{
    print $url." ".get_folder($url)."\n";
}

function get_folder($url)
{
    $url = preg_replace('/(.*)\/.*\..*/', '', $url);
    $url = preg_replace('/\/$/', '', $url);

    $matches = array();
    if (preg_match('/.*\/(.*)/', $url, $matches))
    {
        return $matches[1];
    }

    return '';
}

输出：

www.steptoinstall.com 
www.steptoinstall.com/folder1 folder1
www.steptoinstall.com/folder1 folder1
www.steptoinstall.com/folder1/folder2 folder2
www.steptoinstall.com/folder1/folder2 folder2
www.steptoinstall.com/folder1/folder2 folder2
www.steptoinstall.com/folder1/folder2 folder2

这里可能有一个问题：很难区分 "www.steptoinstall.com/folder1" 和 "www.steptoinstall.com/folder1/index.php" - 如果 SEF url 没有 .php 结尾。

Answer 4

$path = 'www.steptoinstall.com/folder1/folder2/';
$folders = explode('/', $path);
$i = 0;
foreach($folders as $folder) {
    if (strpos($folder, '.') !== FALSE || empty($folder)) {
        unset($folders[$i]);
    }
    $i++;
}
$what_we_need = end($folders);
echo $what_we_need;

很抱歉，我的第一个回答是错的，这应该可以正常工作。

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